Plotting x(2t+2) if x(t) is defined as an anonymous function

I have to plot the function

g = @(t) exp(-t/2)*cos(2*t*pi/3)*u(t);

for g(2t+2). I tried a couple things but I either get a blank graph or just a straight line. The only way it works is if I actually switch all the ts into (2t+2) which is excessivly time consuming

[William Rose]

What did you try?

Answer 1

[William Rose]

@Yakov,

[edit: correct typos (no typos in the code) ]

You need to define u.

If you define the muliplications inside g() with ".*" instead of "*", then you can pass a vector of times to g and get an answer

Given

t=0:.2:10;
u = @(t) double(t>=0); 
g = @(t) exp(-t/2).*cos(2*t*pi/3).*u(t);
plot(t,g(t))

As for 2*t+2:

hold on;  %preserve existing plot
plot(t,g(2*t+2),'-r');

Works.

[Yakov]

That seemed to work, Thanks for the help!

[William Rose]

@Yakov, you're welcome. Please accept the answer if you deem it sufficient.