i get this error "attempting to load ybus script as a function"

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Adegoke Williams
Adegoke Williams 2022 年 9 月 28 日
コメント済み: A.B.M. NOUSHAD BHUIYAN 2024 年 4 月 17 日 18:02
i have added the ybus.m in the command window byt when i try to run the fuction it gives an error message "attempting to load script as a function"
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Geoff Hayes
Geoff Hayes 2022 年 9 月 29 日
@Adegoke Williams - are you referring to the code from the File Exchange found here? Please clarify what you mean by "added the ybus.m in the command window" and show how you are "running the function". Also, please copy and paste the full error message to this post.
Adegoke Williams
Adegoke Williams 2022 年 9 月 29 日
Thanks Geoff, its Exactly that file, i actually trried so many files but got the sa error message. I used the addpath ybus on the command window to add the path to the directory. I tried to run the ybus(z) found in the Power Systems Analysis Textbook , Saadat . When i try to run the ybus(z) either on command window oR LiVESCRIPT, i get the error "Attempt to load ybus script as a function.
>> z = [0, 1, 0, 1.0; 0, 2, 0, 0.8; 1, 2, 0, 0.4; 1, 3, 0, 0.2; 2, 3, 0, 0.2; 3, 4, 0, 0.08]
Y = ybus(z)
z =
0 1.0000 0 1.0000
0 2.0000 0 0.8000
1.0000 2.0000 0 0.4000
1.0000 3.0000 0 0.2000
2.0000 3.0000 0 0.2000
3.0000 4.0000 0 0.0800
Cannot find an exact (case-sensitive) match for 'ybus'
The closest match is: Ybus in C:\Program Files\Polyspace\R2020a\bin\ybus\Ybus.
Did you mean:
>> Y = Ybus(z)
Attempt to execute SCRIPT Ybus as a function:
C:\Program Files\Polyspace\R2020a\bin\ybus\Ybus.m

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採用された回答

David Hill
David Hill 2022 年 9 月 29 日
Not sure what you are doing, but works fine for me.
z = [0, 1, 0, 1.0; 0, 2, 0, 0.8; 1, 2, 0, 0.4; 1, 3, 0, 0.2; 2, 3, 0, 0.2; 3, 4, 0, 0.08];
y=Ybus(z)
y =
0.0000 - 8.5000i 0.0000 + 2.5000i 0.0000 + 5.0000i 0.0000 + 0.0000i 0.0000 + 2.5000i 0.0000 - 8.7500i 0.0000 + 5.0000i 0.0000 + 0.0000i 0.0000 + 5.0000i 0.0000 + 5.0000i 0.0000 -22.5000i 0.0000 +12.5000i 0.0000 + 0.0000i 0.0000 + 0.0000i 0.0000 +12.5000i 0.0000 -12.5000i
function[Ybus] = Ybus(zdata)
nl=zdata(:,1); nr=zdata(:,2); R=zdata(:,3); X=zdata(:,4);
nbr=length(zdata(:,1)); nbus = max(max(nl), max(nr));
Z = R + j*X; %branch impedance
y= ones(nbr,1)./Z; %branch admittance
Ybus=zeros(nbus,nbus); % initialize Ybus to zero
for k = 1:nbr; % formation of the off diagonal elements
if nl(k) > 0 & nr(k) > 0
Ybus(nl(k),nr(k)) = Ybus(nl(k),nr(k)) - y(k);
Ybus(nr(k),nl(k)) = Ybus(nl(k),nr(k));
end
end
for n = 1:nbus % formation of the diagonal elements
for k = 1:nbr
if nl(k) == n | nr(k) == n
Ybus(n,n) = Ybus(n,n) + y(k);
else, end
end
end
end
  6 件のコメント
Adegoke Williams
Adegoke Williams 2022 年 9 月 29 日
Thanks so so much . It works perfectly.
A.B.M. NOUSHAD  BHUIYAN
A.B.M. NOUSHAD BHUIYAN 2024 年 4 月 17 日 18:02
Can you help me to find Y bus admittance matrix for the following "z=[
0 1 0 0.0608 %GEN 1: From ground to bus 1
0 2 0 0.1198 %GEN 2: From ground to bus 2
0 3 0 0.1813 %GEN 3: From ground to bus 3
0 5 0.6841 0.2737 % Transmission line from ground to bus 5
0 6 1.0262 0.3421 % Transmission line from ground to bus 6
0 8 0.9196 0.3219 % Transmission line from ground to bus 8
1 4 0 0.0576 % Transformer from bus 1 to bus 4
2 7 0 0.0625 % Transformer from bus 2 to bus 7
3 9 0 0.0586 % Transformer from bus 3 to bus 9
4 5 0.101 0.085 % Transmission line from bus 4 to bus 5
4 6 0.017 0.092 % Transmission line from bus 4 to bus 6
5 7 0.032 0.161 % Transmission line from bus 5 to bus 7
6 9 0.039 0.170 % Transmission line from bus 6 to bus 9
7 8 0.0085 0.072 % Transmission line from bus 7 to bus 8
8 9 0.0119 0.1008 % Transmission line from bus 8 to bus 9
0 4 0 -1/(0.088+0.079) % Shunt capacitance at bus 4
0 5 0 -1/(0.088+0.153) % Shunt capacitance at bus 5
0 6 0 -1/(0.079+0.179) % Shunt capacitance at bus 6
0 7 0 -1/(0.153+0.0745) % Shunt capacitance at bus 7
0 8 0 -1/(0.0745+0.1045)% Shunt capacitance at bus 8
0 9 0 -1/(0.1045+0.179) % Shunt capacitance at bus 9
]
y=Ybus(zdata)
"

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