Solve 2nd order ODE using Euler Method
古いコメントを表示
VERY new to Matlab...
Trying to implement code to use Euler method for solving second order ODE.
Equation:
x'' + 2*z*w*x' + w*x = 2*sin(2*pi*2*t)
z and w are constants. "t" is time.
Any help would be great.
Thanks!
5 件のコメント
John D'Errico
2022 年 9 月 27 日
編集済み: John D'Errico
2022 年 9 月 27 日
If you need to solve that ODE, then why in the name of god are you writing an Euler's method to solve the ODE. Use ODE45. Do not write your own code. Since the only reason you need to use Euler's method is to do this as a homework assignment, then you need to write your own code. But Answers is not a service where we do your homework with no effort shown by you.
Matt
2022 年 9 月 27 日
Matt
2022 年 10 月 4 日
移動済み: James Tursa
2022 年 10 月 4 日
James Tursa
2022 年 10 月 4 日
@Matt - FYI, when you get errors, it is best to post the entire error message along with your code. Regardless, see my answer below ...
Matt
2022 年 10 月 4 日
採用された回答
その他の回答 (1 件)
Davide Masiello
2022 年 9 月 27 日
編集済み: Davide Masiello
2022 年 9 月 27 日
Hi Matt - a second order ODE can be decomposed into two first order ODEs.
The secret is to set 2 variables y as

The you have

An example code is
clear,clc
tspan = [0,1]; % integrates between times 0 and 1
x0 = [1 0]; % initial conditions for x and dx/dt
[t,X] = ode15s(@odeFun,tspan,x0); % passes functions to ODE solver
x = X(:,1);
dxdt = X(:,2);
plot(t,x)
function dydt = odeFun(t,y)
z = 1;
w = 1;
dydt(1,1) = y(2);
dydt(2,1) = 2*z*w*y(2)-w*y(1)+2*sin(2*pi*2*t);
end
1 件のコメント
Davide Masiello
2022 年 9 月 27 日
For more info, I suggest reading the documentation at the following link.
カテゴリ
ヘルプ センター および File Exchange で Programming についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
