Error "Size input must be scalar"

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Chaudhary P Patel
Chaudhary P Patel 2022 年 9 月 27 日
編集済み: Image Analyst 2022 年 9 月 27 日
Sir, Here delu=randi(30,1), in which i want to add zeros(3,1) but when i am running this in my complete code it is showing "Size input must be scalar".
Please help me out with it.
delu=randi(30,1);
delU=([zeros(3,1);delu]);
  1 件のコメント
Rik
Rik 2022 年 9 月 27 日
編集済み: Image Analyst 2022 年 9 月 27 日
Your code runs without error, as you can see.
delu=randi(30,1);
delU=([zeros(3,1);delu])
delU = 4×1
0 0 0 3

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回答 (1 件)

Image Analyst
Image Analyst 2022 年 9 月 27 日
MATLAB is case sensitive so delu is different than delU. Try this:
delu=randi(30,1) % Generate a single integer in the range 1-30
delu = 9
delu=([zeros(3,1);delu]) % Prepend 3 zeros above that number so it's now 4 rows tall.
delu = 4×1
0 0 0 9
whos delu
Name Size Bytes Class Attributes delu 4x1 32 double
  2 件のコメント
Chaudhary P Patel
Chaudhary P Patel 2022 年 9 月 27 日
delU=([zeros(3,1);delu]) % This is U not u
Image Analyst
Image Analyst 2022 年 9 月 27 日
編集済み: Image Analyst 2022 年 9 月 27 日
OK but it still works, you just have two variables with extremely similar spelling, which of course will be very confusing:
delu=randi(30,1) % Generate a single integer in the range 1-30
delu = 2
delU=([zeros(3,1);delu]) % Prepend 3 zeros above that number so it's now 4 rows tall.
delU = 4×1
0 0 0 2
whos delU
Name Size Bytes Class Attributes delU 4x1 32 double
So why isn't it working for you? You are not even calling the size() function like the error says. You need to give us ALL your code.

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