Replacing value by the mean of the two nearest neighbors
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I have a column vector:
B = [20; 18; NaN; 25; 100; 15; -50; 23]
I need to pre-process data, so I want to:
- replace numbers greater than a certain value (e.g. numbers greater than 40) with the average of the two adjacent numbers.
- replace numbers smaller than a certain value (e.g. numbers smaller than -10) with the average of the two adjacent numbers.
- replace missing value with the average of the two adjacent numbers.
Thank you!
2 件のコメント
Torsten
2022 年 9 月 26 日
The result will depend on the order in which you perform these operations.
So order doesn't matter ?
採用された回答
David Hill
2022 年 9 月 26 日
B = [20; 18; NaN; 25; 100; 15; -50; 23; NaN; 15; -15; 30];
idx=find(isnan(B));
B(idx)=mean([B(idx-1),B(idx+1)],2);
idx=find(B<-10);
B(idx)=mean([B(idx-1),B(idx+1)],2);
idx=find(B>40);
B(idx)=mean([B(idx-1),B(idx+1)],2)
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