Read netCDFs in loop and export to table with different sizes

I am reading several netCDF files with a datetime and corresponding data.
All datafiles have a different lenght, so I thought to find the common range of datetime for all files and save the corresponding data in 1 table so that I have a table like:
[datetime sensor1 sensor2 sensor3 sensor...]
I already found a way to read the files and find the common date but struggle to get evertyhing into 1 table.
Does anyone has a suggestion?
addpath(genpath('./'))
path = 'F:\Waterlevel/';
netCDF = dir([path,strcat('**/Sensor_*')]);
for i = 1:length(netCDF)
baseFilename = netCDF(i).name;
fullFileName = fullfile(path, baseFilename);
fprintf(1, 'Now reading %s\n', fullFileName);
nt = ncread(fullFileName, 'datetime');
Times = datetime(nt, 'convertFrom', 'posixtime', 'Format', 'yyyy-MM-dd HH:mm:ss');
nlevel = ncread(fullFileName, 'level');
[commondates, whereina, whereinb] = intersect(Times,Times(1:length(i)));
firstcommon = commondates(1);
end

 採用された回答

Eric Sofen
Eric Sofen 2022 年 9 月 23 日
編集済み: Eric Sofen 2022 年 9 月 26 日

0 投票

I would suggest using timetable and the synchronize method.
I assume nlevel is the sensor data? If so, build up a cell array of timetables in the loop, then synchronize them.
Edit: fixed concatenation code.
addpath(genpath('./'))
path = 'F:\Waterlevel/';
netCDF = dir([path,'**/Sensor_*']);
alldata = {};
for i = 1:length(netCDF)
baseFilename = netCDF(i).name;
fullFileName = fullfile(path, baseFilename);
fprintf(1, 'Now reading %s\n', fullFileName);
nt = ncread(fullFileName, 'datetime');
Times = datetime(nt, 'convertFrom', 'posixtime', 'Format', 'yyyy-MM-dd HH:mm:ss');
nlevel = ncread(fullFileName, 'level');
alldata = [alldata, {timetable(Times,nlevel)}];
end
finaldata = synchronize(alldata{:},'intersection');

4 件のコメント

Eric Sofen
Eric Sofen 2022 年 9 月 23 日
Also, you don't need the strcat in the dir call.
Siegmund Nuyts
Siegmund Nuyts 2022 年 9 月 26 日
Hi Erik, thanks for your suggestion.
Yes, nlevel is the sensor data.
Using your code, I still get an error "All tables being horizontally concatenated must have the same number of rows"...
Eric Sofen
Eric Sofen 2022 年 9 月 26 日
Whoops! alldata should be built up as a cell array of tables:
alldata = [alldata, {timetable(Times, nlevel)}];
Siegmund Nuyts
Siegmund Nuyts 2022 年 9 月 27 日
That worked perfectly! Thanks a lot

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