evaluate the double integration

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john
john 2022 年 9 月 20 日
コメント済み: john 2022 年 9 月 20 日
May I know I would like to evaluate the double integral of the function and why this error happens and how do I perform the integration?

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Abolfazl Chaman Motlagh
Abolfazl Chaman Motlagh 2022 年 9 月 20 日
You got 2 things wrong (i think) . the error you currently get is for second one. but you will get the error for first one eventually.
first, upper limit of integral shouldn't be function of variable a. because in that case the result of integral would be function of a.
and the other problem is in integral2 function the integration over y (second argument) is first integration so you should change the orders.
syms r theta;
a = 1; %%%%%%%%%%%%%%%%%%%%%%%%
theta_u = -(pi/2);
theta_v = pi/2;
r_u = 0;
r_v = @(theta) (a*cos(theta));
y = @(theta,r) (4 * r.^2 .* cos(theta));
integral2(y,theta_u,theta_v,r_u,r_v)
ans = 1.5708
  1 件のコメント
john
john 2022 年 9 月 20 日
thanks! you solved the problem

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