Hi,
is there a better way to create a simple array of acsending numbers than:
foo = reshape(1:9,3,3)
foo = 3×3
1 4 7 2 5 8 3 6 9
Thanks

 採用された回答

Walter Roberson
Walter Roberson 2022 年 9 月 17 日

0 投票

No, that is the best available -- unless you want to count
foo = reshape(1:9,3,[]) %3 rows, as many colums as needed.
foo = 3×3
1 4 7 2 5 8 3 6 9
If you have the Computer Communications Toolbox, you can use
foo = buffer(1:9, 3) %3 rows
foo = 3×3
1 4 7 2 5 8 3 6 9

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