How to interchange position of a matrix?

A = [3 1 2];

B = [2 3 1];

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X = [2 1 3];

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I want to interchange position of elements in X using A and B.

=> interchange 3rd element of X with 2nd element => X1 = [2 3 1 ]

=> interchange 1st element of X1 with its 3rd element => X2 = [1 3 2]

=> interchange 2nd element of X2 with its fisrt element => X3 = [ 3 1 2]

only need the last output that is X3.

I have tried the following

X(A) = X(fliplr(A))

But not getting how to use both A and B.

Answer 1

[Stephen23]

A = [3,1,2];
B = [2,3,1];
X = [2,1,3];
for k = 1:numel(X)
    X([A(k),B(k)]) = X([B(k),A(k)]);
end
X

X = 1×3

3 1 2

[Ammy]

@Stephen23 thank you very much

Answer 2

[Torsten]

Are you sure that the changes should be performed subsequently with the new vectors obtained from the steps before ?

My guess would be that the 3rd element of X should be replaced by the 2nd element of X, the 1st element of X should be replaced with the 3rd element of X and the 2nd element of X should be replaced with the 1st element of X, resulting in [ 3 2 1].

If your interpretation is correct, use a loop:

A = [3 1 2];
B = [2 3 1];

X = [2 1 3];
for i = 1:numel(X)
    tmp = X(A(i));
    X(A(i)) = X(B(i));
    X(B(i)) = tmp;
end
X

X = 1×3

3 1 2

[Ammy]

@Torsten Yes, my interpretation is the same and your answer fulfill that. Thank you very much.