i have one dimensional array and i want to move every non zero element oh that array to exchange position with every zero in each iteration.

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Muhammad 2022 年 8 月 30 日
コメント済み: John D'Errico 2022 年 8 月 30 日
For example
a=[1 2 3 4 0 0 0 ]
I want all the possible combination through nested for loop (not circular shift)
example of Iterations are like
4 will replace its position with 0 (on the right)
a1=[1 2 3 0 4 0 0]
a2=[1 2 3 0 0 4 0]
a3=[1 2 3 0 0 0 4]
now 4 returns to its original position and 3 will shift its position with 0 (on right on 4) move left place one by one
a4=[1 2 0 4 3 0 0]
a5=[1 2 0 4 0 3 0]
a6=[1 2 0 4 0 0 3]
now 3 returns to its original position and 2 replaces its position with 0 (right of 4) move left place one by one
a7=[1 0 3 4 2 0 0 ]
a8=[1 0 3 4 0 2 0 ]
a9=[1 0 3 4 0 0 2 ]
now 2 reutrns to its original position and 1 replaces its position with 0
a10=[0 2 3 4 1 0 0]
a11=[0 2 3 4 0 1 0]
a12=[0 2 3 4 0 0 1]
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John D'Errico 2022 年 8 月 30 日
Are you sure this is what you want? It seems like you might want ALL ways of sorting the elements of the array, and this gives you only a subset of the permutations.

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回答 (1 件)

the cyclist 2022 年 8 月 30 日

I think this does what you want:
% Input data
a = [1 2 3 4 0 0 0];
% Find the indices of the non-zeros and the zeros
idxNotZero = find(a~=0);
idxZero = find(a==0);
% Preallocate the array c that holds the output
numberCombos = numel(idxNotZero).*numel(idxZero);
c = zeros(numberCombos,numel(a));
% For all pairs of zero and non-zero elements, write a new row that swaps
% them
nr = 0;
for inz = idxNotZero
for iz = idxZero
nr = nr + 1;
c(nr,:) = swapIt(a,inz,iz);
end
end
c
c = 12×7
0 2 3 4 1 0 0 0 2 3 4 0 1 0 0 2 3 4 0 0 1 1 0 3 4 2 0 0 1 0 3 4 0 2 0 1 0 3 4 0 0 2 1 2 0 4 3 0 0 1 2 0 4 0 3 0 1 2 0 4 0 0 3 1 2 3 0 4 0 0
% Function that swaps two elements of a vector, given the element indices
function [out] = swapIt(a,i,j)
out = a;
out([i j]) = out([j i]);
end

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