what dose z represent in this graph?

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Aisha Mohamed
Aisha Mohamed 2022 年 8 月 26 日
コメント済み: Torsten 2022 年 8 月 26 日
I am studying these graphs , and I really confused in some points here.
1- when we take arbitrary point in this figure for example as we can see in the first figure (x= -0.465, y=0.325, z=0.0084), we see that z>0 (greter than 0)
but when we calculate (cos(angle(-0.465+0.325i))) , we got it = -.8196 <0 (les than zero ))
it is clear from this figure z does not equal the value of the function (cos(angle(-0.465+0.325i))), and
if z indicate to the sign of this function , why we got z>0 whereas the value of this function <o?
My questions are,
Is z in this figure indiacet to the value of (cos(angle(-0.465+0.325i))) or only tells us where (cos(angle(-0.465+0.325i))) positinve and negative? and why we find this contrast?
I will appreciate any help.
  5 件のコメント
Walter Roberson
Walter Roberson 2022 年 8 月 26 日
My answer was in preparation when you posted yours. We happened to close to the same thing.
Torsten
Torsten 2022 年 8 月 26 日
Maybe I'm blind, but where do you get from that f_k(z) = z ?

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