- Find the coordinates of points in the white region.
- Find the point belonging to the white region, which is at the maximum distance from the lower-right corner of the image.
- Use the maximum distance obtained as the radius to draw the quarter circle.
How do I calculate eccentricity or RMSE value from black and white image?
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Hello,
I have a question regrading to image analysis.
Here, I have a image like this black and white image.
i=imread(['BW_20220804_0301.jpg'])
imshow(i)
I want to calculate how much this quarter-circular shaped image (white area) eccentric when we impose ideal quarter circle.
Also, I want to know a radius of the ideal quarter circle.
How can I make this?
Thanks, HyoJae.
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回答 (1 件)
  Udit06
      
 2023 年 9 月 1 日
        Hi HyoJae, 
I understand that you want to make a quarter circle which is just large enough to cover the entire white region in your binary image. Assuming the white region is always at the lower-right corner of the image, you can follow the steps mentioned below: 
Here is the implementation of above steps in MATLAB: 
binaryImage=imread("BW_20220804_0301.jpg"); 
% Step 1: Find the coordinates of the white object 
[rows, cols] = find(binaryImage == 1); 
minX = min(cols); 
maxY = max(rows); 
% Step 2: Calculate the radius of the quarter circle 
fig_size=2150; 
radius= max(sqrt((cols-fig_size).^2 + (rows-fig_size).^2)) 
% Step 3: Draw the quarter circle on the image 
figure; 
imshow(binaryImage); % Replace 'yourImage' with your actual image 
hold on; 
% Calculate the center point of the quarter circle 
center = [size(binaryImage, 2), size(binaryImage, 1)]; 
% Draw the quarter circle using the 'rectangle' function 
rectangle('Position', [center(1) - radius, center(2) - radius, radius*2, radius*2], ... 
    'Curvature', [1, 1], 'EdgeColor', 'r', 'LineWidth', 2); 
hold off; 
To determine the extent to which the white region deviates from an ideal quarter circle, you can calculate the area difference between the white region and the corresponding ideal quarter circle. 
I hope this helps. 
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