# How to solve a system of two linear equations in matrix form under a loop /

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Adnan Hayat 2022 年 7 月 28 日
コメント済み: Jon 2022 年 8 月 2 日
Suppose that I have two coordinates, time and space , and two dependent variables c and T such that and . Now I have a system of two coupled equations which are given in matrices form as
I define the t and x vectors in the code as follows. How to calculate the matrix X inside the loops given below. Initial data is available, i.e. and are given.
for j=1:50
t(j)=j*0.05; % t vector
end
for i=1:50
x(i)=i*0.05; % space vector
end
%___________________________ running the loop_______________________________________
for j=1:50
for i=1:50
%???????? How to calculate the matric X here ????????????????????
end
end
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Adnan Hayat 2022 年 7 月 29 日
No, it is not a typo. Actually i define x and t vectors like that. YOu can ignore that and take x=1,2,3,...,50 and t=1,2,3,...,50

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### 回答 (1 件)

Jon 2022 年 7 月 28 日

I'll assume you know how to calculate A and B based upon your c and T values. Then to solve for X use
X = M\(J*A + B)
Note that using the \ operator is more numerically robust and efficient than actually computing the matrix inverse of M
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Jon 2022 年 8 月 2 日
You could store the results in a 3 dimensional array, so
X = zeros(2,50,50); % preallocate
for i = 1:50
for j = 1:50
.
.
.
X(:,i,j) = M\(J*A + B)
end
end

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