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suppose i have number a=5.70787644444 how do i consider just first 2 decimal places in that . that is a=5.70. is it possible?

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please reply as soon as possible.

採用された回答

Star Strider
Star Strider 2015 年 2 月 7 日
One solution:
a = 5.70787644444;
roundn = @(x,n) fix(x.*10.^n)./10.^n; % Round ‘x’ To ‘n’ Digits To The Right Of The Decimal
ar = roundn(a,2)
produces:
ar =
5.70
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その他の回答 (1 件)

Guillaume
Guillaume 2015 年 2 月 7 日
Since 2014b, round takes the number of decimals to round to, so it's just:
a = 5.70787644444;
arounded = round(a, 2)
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Image Analyst
Image Analyst 2015 年 2 月 7 日
Yes, but he didn't ask for the rounded value. You probably just thought that since that's the name Star chose - not a good descriptive name in my opinion since it uses fix() instead of round() and fix() does not round in the sense that most people think of rounding.

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