Replacing elements in a vector
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The values of an array match the index of elements in a vector. For example, the value of 5 in array1 below corresponds to whatever is in index 5 in vector1, i.e. the number 3 in this case. So how do I replace the value of the original number in array1 in the example by the number at the corresponding index in vector1? I realize this is a little confusing, so here's a mini example of what I want to do:
array1 = [1 2; 4 2; 5 5; 4 2];
vector1 = [2 1 1 4 3 4];
result = [2 1; 4 1; 3 3; 4 1];
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Paul
2022 年 7 月 17 日
array1 = [1 2; 4 2; 5 5; 4 2];
vector1 = [2 1 1 4 3 4];
result = [2 1; 4 1; 3 3; 4 1]
result1 = vector1(array1)
3 件のコメント
Paul
2022 年 7 月 17 日
vector1(array1) treats each entry of array1 as the linear index into vector1. The output takes the same shape as array1. It's the same as
array1 = [1 2; 4 2; 5 5; 4 2];
vector1 = [2 1 1 4 3 4];
reshape(vector1(array1(:)),size(array1))
その他の回答 (1 件)
DGM
2022 年 7 月 16 日
Your example isn't consistent. I'm assuming you want this:
A = [10 20; 30 40; 50 60];
idx = [2 1; 1 4; 3 3];
B = A.';
B = B(idx)
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