Please find the mistake in this code.

Reference image: plot should be like this but don't know where I am making mistake.
syms x lambda
warning off
alpha = -0.1;
sigma = 0.1;
eps = -0.1;
e = 0.2;
M = 10;
a = 2;
figure
psi_list = [10, 20, 30, 40. 50];
for i = 1:numel(psi_list)
psi = psi_list(i);
hbar = @(x) a - a.*x + x;
A1 = eps + alpha^3 + (3 * sigma^2 * alpha);
B1 =@(x,lambda) (-3 * lambda * M) * ((hbar(x).^2) + (2 .* hbar(x) .* alpha) + (sigma^2) + (alpha^2));
a1 =@(x) tanh(M .* hbar(x));
b1 =@(x) 1 - ((tanh(M .* hbar(x))).^2);
c1 = (M * alpha) - ((M^3 * A1)/3);
d1 = @(lambda) 2 * (M^2) * (1 + lambda);
C1=@(x) a1(x) + (b1(x) .* c1);
D1 =@(x,lambda) d1(lambda) .* ((hbar(x).^3) + (3 .* (hbar(x).^2) .* alpha) + (3 .* hbar(x) .* (alpha)^2) + (3 .* hbar(x) .* (sigma)^2) + eps + (3 * alpha * (sigma^2)) + (alpha^3));
f1 =@(x,lambda) B1(x,lambda) + (3 * lambda .* C1(x) .* hbar(x)) + (3 * lambda .* C1(x) .* alpha) + (D1(x,lambda) .* C1(x));
f2 =@(x,lambda) 12 * (M^2) * (1 + lambda) .* C1(x);
f3 = psi * (e^3);
f4 = @(lambda) (1 + lambda) *180 * ((1 - e)^2);
f5 =@(lambda) 1/(2 + lambda);
F = @(x,lambda) ((f5(lambda) .* f1(x,lambda))./f2(x,lambda)) + (f3/f4(lambda));
q1 =@(x,lambda) hbar(x) ./ (2 .* F(x,lambda));
Q1 = int(q1,x,0,1); % integration with respect to "x" limit 0 to 1
q2 = @(x,lambda) 1./(F(x,lambda));
Q2 = int(q2,x,0,1); % integration with respect to "x" limit 0 to 1
Q = @(lambda) Q1(lambda)/Q2(lambda); % Q is a function of "lambda"
p1 = @(x,lambda) (1./F(x,lambda)) .* ((0.5 .* hbar(x)) - Q(lambda));
P = @(x,lambda) int(p1,x); % integration with respect to "x" limit 0 to x
% W is obtained by integrating "P" with respect to x limit to x is 0 to
% 1
W =@(lambda) int(P,x,0,1);
fplot(@(lambda) W(lambda))
end
legend(num2str(psi_list'))
ylim([0 1])
xlim([0 4])
set(gca, 'ytick', 0:0.1:1);
set(gca, 'xtick', 0:0.2:4);
xlabel('lambda')
ylabel('W(lambda)')

6 件のコメント

dpb
dpb 2022 年 7 月 8 日
No have symbolic TB here, sorry.
I'd suggest working through logic w/ debugger to see where it fails to do as expected first...
Steven Lord
Steven Lord 2022 年 7 月 8 日
warning off
I strongly recommend you not do this. MATLAB doesn't issue warnings "just because", it issues warnings because it sees something in the code that may cause a problem later or may indicate that the code isn't doing what you think it's doing.
So when you eliminate that line of code, what warnings get issued? Show the full and exact text of those messages (all the text displayed in orange in the Command Window.) Those warnings may very well explain why you're not seeing anything on your axes.
AVINASH SAHU
AVINASH SAHU 2022 年 7 月 8 日
Warning: Error updating FunctionLine.
The following error was reported evaluating the function in FunctionLine update: Invalid indexing or function definition. Indexing must follow MATLAB
indexing. Function arguments must be symbolic variables, and function body must be sym expression.
Warning: Error updating FunctionLine.
The following error was reported evaluating the function in FunctionLine update: Invalid indexing or function definition. Indexing must follow MATLAB
indexing. Function arguments must be symbolic variables, and function body must be sym expression.
Warning: Error updating FunctionLine.
The following error was reported evaluating the function in FunctionLine update: Invalid indexing or function definition. Indexing must follow MATLAB
indexing. Function arguments must be symbolic variables, and function body must be sym expression.
Warning: Error updating FunctionLine.
The following error was reported evaluating the function in FunctionLine update: Invalid indexing or function definition. Indexing must follow MATLAB
indexing. Function arguments must be symbolic variables, and function body must be sym expression.
Warning: Error updating FunctionLine.
The following error was reported evaluating the function in FunctionLine update: Invalid indexing or function definition. Indexing must follow MATLAB
indexing. Function arguments must be symbolic variables, and function body must be sym expression.
sorry I forgot to apply "hold on" command. After applying this I am getting the above mentioned warning
AVINASH SAHU
AVINASH SAHU 2022 年 7 月 8 日
syms x lambda
% warning off
alpha = -0.1;
sigma = 0.1;
eps = -0.1;
e = 0.2;
M = 10;
a = 2;
figure
hold on
psi_list = [10, 20, 30, 40. 50];
for i = 1:numel(psi_list)
psi = psi_list(i);
hbar = @(x) a - a.*x + x;
A1 = eps + alpha^3 + (3 * sigma^2 * alpha);
B1 =@(x,lambda) (-3 * lambda * M) * ((hbar(x).^2) + (2 .* hbar(x) .* alpha) + (sigma^2) + (alpha^2));
a1 =@(x) tanh(M .* hbar(x));
b1 =@(x) 1 - ((tanh(M .* hbar(x))).^2);
c1 = (M * alpha) - ((M^3 * A1)/3);
d1 = @(lambda) 2 * (M^2) * (1 + lambda);
C1=@(x) a1(x) + (b1(x) .* c1);
D1 =@(x,lambda) d1(lambda) .* ((hbar(x).^3) + (3 .* (hbar(x).^2) .* alpha) + (3 .* hbar(x) .* (alpha)^2) + (3 .* hbar(x) .* (sigma)^2) + eps + (3 * alpha * (sigma^2)) + (alpha^3));
f1 =@(x,lambda) B1(x,lambda) + (3 * lambda .* C1(x) .* hbar(x)) + (3 * lambda .* C1(x) .* alpha) + (D1(x,lambda) .* C1(x));
f2 =@(x,lambda) 12 * (M^2) * (1 + lambda) .* C1(x);
f3 = psi * (e^3);
f4 = @(lambda) (1 + lambda) *180 * ((1 - e)^2);
f5 =@(lambda) 1/(2 + lambda);
F = @(x,lambda) ((f5(lambda) .* f1(x,lambda))./f2(x,lambda)) + (f3/f4(lambda));
q1 =@(x,lambda) hbar(x) ./ (2 .* F(x,lambda));
Q1 = int(q1,x,0,1); % integration with respect to "x" limit 0 to 1
q2 = @(x,lambda) 1./(F(x,lambda));
Q2 = int(q2,x,0,1); % integration with respect to "x" limit 0 to 1
Q = @(lambda) Q1(lambda)/Q2(lambda); % Q is a function of "lambda"
p1 = @(x,lambda) (1./F(x,lambda)) .* ((0.5 .* hbar(x)) - Q(lambda));
P = @(x,lambda) int(p1,x); % integration with respect to "x" limit 0 to x
% W is obtained by integrating "P" with respect to x limit of x is 0 to
% 1
W =@(lambda) int(P,x,0,1);
fplot(@(lambda) W(lambda))
end
legend(num2str(psi_list'))
ylim([0 1])
xlim([0 4])
set(gca, 'ytick', 0:0.1:1);
set(gca, 'xtick', 0:0.2:4);
xlabel('lambda')
ylabel('W(lambda)')
Warning: Error updating FunctionLine.

The following error was reported evaluating the function in FunctionLine update: Invalid indexing or function definition. Indexing must follow MATLAB indexing. Function arguments must be symbolic variables, and function body must be sym expression.
Sam Chak
Sam Chak 2022 年 7 月 8 日
Can you plot the lines manually one by one? You'll definitely find out what went wrong then.
AVINASH SAHU
AVINASH SAHU 2022 年 7 月 8 日
okay thank you

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 採用された回答

Torsten
Torsten 2022 年 7 月 8 日
編集済み: Torsten 2022 年 7 月 8 日

0 投票

alpha = -0.1;
sigma = 0.1;
eps = -0.1;
e = 0.2;
M = 10;
a = 2;
%figure
psi_list = [10, 20, 30, 40, 50];
lambda = 0:0.2:4;
for i = 1:numel(psi_list)
psi = psi_list(i);
hbar = @(x) a - a.*x + x;
A1 = eps + alpha^3 + (3 * sigma^2 * alpha);
B1 =@(x,lambda) (-3 * lambda * M) * ((hbar(x).^2) + (2 .* hbar(x) .* alpha) + (sigma^2) + (alpha^2));
a1 =@(x) tanh(M .* hbar(x));
b1 =@(x) 1 - ((tanh(M .* hbar(x))).^2);
c1 = (M * alpha) - ((M^3 * A1)/3);
d1 = @(lambda) 2 * (M^2) * (1 + lambda);
C1=@(x) a1(x) + (b1(x) .* c1);
D1 =@(x,lambda) d1(lambda) .* ((hbar(x).^3) + (3 .* (hbar(x).^2) .* alpha) + (3 .* hbar(x) .* (alpha)^2) + (3 .* hbar(x) .* (sigma)^2) + eps + (3 * alpha * (sigma^2)) + (alpha^3));
f1 =@(x,lambda) B1(x,lambda) + (3 * lambda .* C1(x) .* hbar(x)) + (3 * lambda .* C1(x) .* alpha) + (D1(x,lambda) .* C1(x));
f2 =@(x,lambda) 12 * (M^2) * (1 + lambda) .* C1(x);
f3 = psi * (e^3);
f4 = @(lambda) (1 + lambda) *180 * ((1 - e)^2);
f5 =@(lambda) 1./(2 + lambda);
F = @(x,lambda) ((f5(lambda) .* f1(x,lambda))./f2(x,lambda)) + (f3./f4(lambda));
q1 =@(x,lambda) hbar(x) ./ (2 .* F(x,lambda));
Q1 = @(lambda)integral(@(x)q1(x,lambda),0,1,'ArrayValued',true); % integration with respect to "x" limit 0 to 1
q2 = @(x,lambda) 1./(F(x,lambda));
Q2 = @(lambda)integral(@(x)q2(x,lambda),0,1,'ArrayValued',true); % integration with respect to "x" limit 0 to 1
Q = @(lambda) Q1(lambda)./Q2(lambda); % Q is a function of "lambda"
p1 = @(x,lambda) (1./F(x,lambda)) .* ((0.5 .* hbar(x)) - Q(lambda));
P = @(x,lambda) integral(@(y)p1(y,lambda),0,x,'ArrayValued',true); % integration with respect to "x" limit 0 to x
% W is obtained by integrating "P" with respect to x limit to x is 0 to
% 1
W =@(lambda) integral(@(x)P(x,lambda),0,1,'ArrayValued',true);
%fplot(@(lambda) W(lambda))
plot(lambda,W(lambda))
hold on
end
legend(num2str(psi_list'))
ylim([0 1])
xlim([0 4])
set(gca, 'ytick', 0:0.1:1);
set(gca, 'xtick', 0:0.2:4);
xlabel('lambda')
ylabel('W(lambda)')

1 件のコメント

AVINASH SAHU
AVINASH SAHU 2022 年 7 月 8 日
Thank you so much. It helped me a lot

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