How to turn a Yes/No cell array into binary (0-1)

I have a Yes/No cell array of 4000x1 and want to turn it into a binary system

Thanks for your attention

Answer 1

[Jon]

 A = {true,false;false,true}

A = 2×2 cell array
    {[1]}    {[0]}
    {[0]}    {[1]}

 B = cell2mat(A)

B = 2×2 logical array
   1   0
   0   1

[Rafael Borobio Castillo]

It is a Yes No cell array but some of them display NA. At the moment I try to use cell2mat y mentions the following:

Error using cat

Dimensions of arrays being concatenated are not consistent.

Error in cell2mat (line 83)

m{n} = cat(1,c{:,n});

Error in BAR_CHART (line 19)

C_2 = cell2mat(B_2);

Thanks

[Jon]

Please save your array to a .mat file and attach it so that I can see exactly what you have

[Jon]

If your data are character arrays, with the words yes or no you can do this

A = {'Yes','no';'no','yes'}

A = 2×2 cell array
    {'Yes'}    {'no' }
    {'no' }    {'yes'}

B = strcmpi(A,'yes') % use strcmpi rather than strcmp so it will be case insensitive

B = 2×2 logical array
   1   0
   0   1

[Jon]

When you say that your matrix contains NA, does that stand for Not Applicable. Since the result is binary true or false you can't have a binary array that has three kinds of values, so you have to pick either true or false for the NA's. The above code will work however it will consider NA to be false. If you want them to be true, you could do something like

B = strcmpi(A,'yes')|strcmpi(A,'NA')

[Jon]

Did this solve your problem? If so please accept the answer so others will know that a solution is available

Answer 2

[ajay kumar]

m = {true,false;false,true};
for i = 1:numel(m)
    disp(m(i))
end

    {[1]}

    {[0]}

    {[0]}

    {[1]}