# How to apply moving harmonic average on an array?

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Nisar Ahmed 2022 年 7 月 3 日

Hi,
I have attached the data Kd_i = (115*1), I want to keep first and last values as it is in the data (or also shown in the figure below) and in the row want compute the harmonic average of first and second values (red square), in the 3rd row I want to compute the harmonic average of second and thrid values (green square) asn so on...
I mean first and last values remain same (just to have final array/vector of equal length), and then from second row it moves the by computing the harmonic mean of first and second row, until second last row. Can someone help me to write it code?
Thanks

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### 採用された回答

Abhishek Tiwari 2022 年 7 月 3 日
Hi,
A 'For' loop and harmmean() may do the same thing, as shown.
n = numel(Kd_i);
harmonicMean = Kd_i;
for idx = 2:n-1
harmonicMean(idx) = harmmean(Kd_i(idx-1 : idx, 1));
end
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Abhishek Tiwari 2022 年 7 月 4 日
Yeah, harmonicMean has first and last values from Kd_i, and the remaining are the harmonic means of two rows (prev. and current).
Nisar Ahmed 2022 年 7 月 4 日
thanks

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### その他の回答 (2 件)

Star Strider 2022 年 7 月 3 日
If you want to calculate it as described in the harmmean More About section, perhaps something like this would work —
movhm = @(x) 2./movsum(1./x,2);
v = 1:5
v = 1×5
1 2 3 4 5
movhm(v)
ans = 1×5
2.0000 1.3333 2.4000 3.4286 4.4444
would work.
.
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dpb 2022 年 7 月 3 日

Simplest is probably just brute-force --
HM=[Kd_1(1) arrayfun(@(i)harmmean(Kd_1(i:i+1)),1:numel(Kd_1)-1) Kd_1(end)].';
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Nisar Ahmed 2022 年 7 月 4 日
@dpb What is K here; harmmean(K(i:i+1)), is it the same Kd_i? and if I change as K = Kd_i, following error appears
Error using vertcat
Dimensions of arrays being concatenated are not consistent.
Error in Const_Q_Full_Mackbeth (line 90)
Kd_HM = [Kd_i(1); arrayfun(@(i)harmmean(Kd_i(i:i+1)),1:numel(Kd_i)-1);Kd_i(end)];
dpb 2022 年 7 月 4 日
Yeah, I made a local array of K=Kd_1(1:15) so wasn't too much to look at in command window...then didn't fix -- and arrayfun returns row vector didn't transpose...

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