How to apply moving harmonic average on an array?

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Nisar Ahmed
Nisar Ahmed 2022 年 7 月 3 日
編集済み: dpb 2022 年 7 月 4 日
I have attached the data Kd_i = (115*1), I want to keep first and last values as it is in the data (or also shown in the figure below) and in the row want compute the harmonic average of first and second values (red square), in the 3rd row I want to compute the harmonic average of second and thrid values (green square) asn so on...
I mean first and last values remain same (just to have final array/vector of equal length), and then from second row it moves the by computing the harmonic mean of first and second row, until second last row. Can someone help me to write it code?


Abhishek Tiwari
Abhishek Tiwari 2022 年 7 月 3 日
A 'For' loop and harmmean() may do the same thing, as shown.
n = numel(Kd_i);
harmonicMean = Kd_i;
for idx = 2:n-1
harmonicMean(idx) = harmmean(Kd_i(idx-1 : idx, 1));
  3 件のコメント
Nisar Ahmed
Nisar Ahmed 2022 年 7 月 4 日


その他の回答 (2 件)

Star Strider
Star Strider 2022 年 7 月 3 日
If you want to calculate it as described in the harmmean More About section, perhaps something like this would work —
movhm = @(x) 2./movsum(1./x,2);
v = 1:5
v = 1×5
1 2 3 4 5
ans = 1×5
2.0000 1.3333 2.4000 3.4286 4.4444
would work.

dpb 2022 年 7 月 3 日
編集済み: dpb 2022 年 7 月 4 日
Simplest is probably just brute-force --
HM=[Kd_1(1) arrayfun(@(i)harmmean(Kd_1(i:i+1)),1:numel(Kd_1)-1) Kd_1(end)].';
  2 件のコメント
dpb 2022 年 7 月 4 日
Yeah, I made a local array of K=Kd_1(1:15) so wasn't too much to look at in command window...then didn't fix -- and arrayfun returns row vector didn't transpose...



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