how to use if-else for select transition matrix input

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Anuchit Wibun
Anuchit Wibun 2015 年 2 月 3 日
コメント済み: Michael Haderlein 2015 年 2 月 4 日
d = 1,2,5,10 will use tm = p_clear but d = 3,4,7 will use tm = p_partly and d = 6,8,9 will use tm = p_cloudy. what command that i should use? The below is code that i wrote but it has problem about transition matrix that used not match with day. pleas help me.
if d == 1 || d == 2 || d == 3 | d == 4 || d == 5 || d == 7 || d == 17;
p = cdf_partly;
elseif d == 6 || d == 8 || d == 9 || d == 10;
p = cdf_mostly;
end

採用された回答

Julia
Julia 2015 年 2 月 3 日
Hi,
I do not completely understand your problem, but you can write your conditions with a switch-case statement:
function p = test2(y)
switch y
case {1, 2, 5, 10};
p=0;
case {3, 4, 7};
p=1;
case {6, 8, 9};
p=2;
otherwise
p=-1;
end
end
  6 件のコメント
Anuchit Wibun
Anuchit Wibun 2015 年 2 月 4 日
I have file in worksheet its name "day". In this file is array of number [1; 1; 1; 2; 2; 2; 3; 3; 3; 4; 4; 4....,10]. From my code, i define "d" is value that read from day file in each row. That mean d=1,d=1,d=1,d=2,d=2,d=2...] and i create loop if d==1, i will determine p = cdf_clear(cdf_clear is matrix 10*10) but d==2, i will determine p=cdf_parlty(it not same cdf_clear). The result that i want is
output file : @ day 1 >> 0.34 [value that was got from *cdf_clear* (i,j)]
1 >> 0.85 [value that was got from *cdf_clear* (i,j)]
......
2 >> 0.23 [value that was got from *cdf_partly* (i,j)]
.....
3 >> 0.26 [value that was got from *cdf_mostสั* (i,j)]
Are you understand with i explain?. I used if-else
if d==1 || d==3 || d==7;
p = cdf_clear;
elseif d==4 || d== 5;
p = cdf_partly;
end.
It not work. I'm beginner, i try to watch technique from internet but i don't know keyword for thing that i want. Thank you every much.
Michael Haderlein
Michael Haderlein 2015 年 2 月 4 日
Ok, but what is the problem with Julia's answer? If you replace p=0 with p=cdf_clear and so on, it should work.

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