Is it possible to get the path of a file using uigetfile() ?

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Hamlet López
Hamlet López 2022 年 6 月 23 日
編集済み: Hamlet López 2022 年 6 月 23 日
What I want to do is get the path of a file that user selects, lets say an image is in downloads folder (example: 'C:\Users\%UserName%\Downloads\image.png').
So when executing the script the path of file is saved in a string and showed in command window.
Right now I have no succes with the following, I'm I using the correct functions for this?
filepath = fileparts( uigetfile() );
disp(['This is the file path: ',filepath]);

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Walter Roberson
Walter Roberson 2022 年 6 月 23 日
[filename, filepath] = uigetfile();
if ~ischar(filename); return; end %user cancel
fullname = fullfile(filepath, filename);
fprintf('This is the file path: %s\n', fullname);
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Hamlet López
Hamlet López 2022 年 6 月 23 日
OK, this is what I was looking for. Thank you very much Sir.

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