matrix array

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Tom Fredrick
Tom Fredrick 2011 年 10 月 4 日
Please can someone be of help? Here is my code below:
a=[2 2 2 2 4 4 4 4];
b = [0 0 0 0 1 1 1 1];
c = Shuffle(b);
d = c(a)
When I finished inputting the code, d returned 8 zeros. Instead I want after randomizing c, then d will return two (zeros) and two(ones) that tally with the four (2's) and four (4's)in the first variable a. In other words,I want d to return two zeros and two ones for the 2's and the same also for the 4's regardless of the order. In essence I want d to return something like this: d = 0 1 0 1 1 0 0 1 OR 0 0 1 1 0 1 1 0. Thanks in advance, Tom.
  2 件のコメント
Fangjun Jiang
Fangjun Jiang 2011 年 10 月 4 日
what is shuffle()?
Tom Fredrick
Tom Fredrick 2011 年 10 月 4 日
shuffle rearranges the elements in a random order.

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回答 (2 件)

the cyclist
the cyclist 2011 年 10 月 4 日
I don't really understand what you want. But I think you can probably make good use of the randperm() command.

Fangjun Jiang
Fangjun Jiang 2011 年 10 月 4 日
Okay, shuffle() is your own function. I can do that using randperm() like cyclist suggested. It's basically the same.
a=[2 2 2 2 4 4 4 4];
b = [0 0 0 0 1 1 1 1];
c = b(randperm(length(b)));
d = c(a)
Since a is [2 2 2 2 4 4 4 4], so d will be the 2nd and 4th value of c, each repeats 4 times. So d has 4 possible answer.
  1. all zeros
  2. all ones
  3. four zeros and then four ones
  4. four ones and then four zeros
Please double check your logic to see if you missed anything.
Considering your expected output, maybe all you need is:
d=b(randperm(length(b)))
  1 件のコメント
Tom Fredrick
Tom Fredrick 2011 年 10 月 6 日
Thanks Fangjun.
Tom

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