concatenate matrix with zeros function

2 ビュー (過去 30 日間)
Ashis Pandey
Ashis Pandey 2022 年 6 月 15 日
編集済み: per isakson 2022 年 6 月 15 日
if I have matrix a = [2 3 4; 5 6 7; 8 9 1],
zeros = (a, 2)
is this a valid code? because one of my working code has this. if so how does the output look like ?
  7 件のコメント
Ashis Pandey
Ashis Pandey 2022 年 6 月 15 日
In short, if I have matrix a = [2 3 4; 5 6 7; 8 9 1],
zeros = (a, 2)
Why this above code don’t work but the below one(see the third line with zeros function in it) works although both are similar?
%Get antenna pairs and convert to matlab matrix
ants_pairs = vtrigU.vtrigU.GetAntennaPairs(mySettings.txMode);
TxRxPairs = zeros(ants_pairs.Length,2);
for ii = 1: ants_pairs.Length
TxRxPairs(ii,1) = double(ants_pairs(ii).tx);
TxRxPairs(ii,2) = double(ants_pairs(ii).rx);
end
per isakson
per isakson 2022 年 6 月 15 日
編集済み: per isakson 2022 年 6 月 15 日
Let me guess. The value of ants_pairs.Length is a scalar. The word, Length, supports that. The value of a is a 2D array. See zeros.
zeros([2,3],4)
Error using zeros
Size inputs must be scalar.

サインインしてコメントする。

回答 (1 件)

Chunru
Chunru 2022 年 6 月 15 日
The code "TxRxPairs = zeros(ants_pairs.Length,2)" is correct. It has the function name "zeros" followed by the arguments inside the brackets. The first argument "ants_pairs.Length" is a scalar rather a vector or matrix.
> In short, if I have matrix a = [2 3 4; 5 6 7; 8 9 1],
> zeros = (a, 2)
The statement of "zeros = (a, 2)" is wrong. First, the correct stament should be function name (zeros) followed by arguments inside brackets, say
% x = zeros(a, 2) % wrong
Even the above is still not correct, as a is not a scalar. So the correct statement should be
a = [2 3 4; 5 6 7; 8 9 1];
x = zeros(size(a)) % where size(a0 = [3 3]
x = 3×3
0 0 0 0 0 0 0 0 0
The above is correct in syntax. But we don't know if it is what you want.
You can also have:
y = zeros(a(1,1), 2) % where a(1,1) is a scalar
y = 2×2
0 0 0 0

カテゴリ

Help Center および File ExchangeCreating and Concatenating Matrices についてさらに検索

製品


リリース

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by