How may one digitize a curve from an image

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CD
CD 2022 年 6 月 14 日
回答済み: Image Analyst 2022 年 6 月 14 日
The attached jpeg contains battery discharge curves at various discharge currents (0.68 to 10 A).
I'd like to create arrays (stored in a .mat file) which contains these discharge curves (voltage vs capacity).
Ideally I just need the data for the 0.68 A curve.
How would one "digitize" the 0.68A curve into X and Y coordinates/values given a minimum step size?
Thank you

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DGM
DGM 2022 年 6 月 14 日
編集済み: DGM 2022 年 6 月 14 日
These two answers are relevant and contain links to other related answers.
Long story short, accuracy will be limited, and trying to write something that will automagically find the right curve is almost always going to be a waste of time, especially if you only have one plot to transcribe. Just manually transcribe the curve as described. I've attached an SVG file that's already had a spline fit to it. The SVG processing is as described in the answers above.
% using the following FEX tools:
% https://www.mathworks.com/matlabcentral/fileexchange/72225-load-svg-into-your-matlab-code
% filename of manually-fit svg file
fname = 'discharge_curves.svg';
% data range from original image axis labels
xrange = [0 4000];
yrange = [0 5];
% spline discretization parameter [0 1]
coarseness = 0.001;
% get plot box geometry
str = fileread(fname);
str = regexp(str,'((?<=<rect)(.*?)(?=\/>))','match');
pbx = regexp(str,'((?<=x=")(.*?)(?="))','match');
pby = regexp(str,'((?<=y=")(.*?)(?="))','match');
pbw = regexp(str,'((?<=width=")(.*?)(?="))','match');
pbh = regexp(str,'((?<=height=")(.*?)(?="))','match');
pbrect = [str2double(pbx{1}{1}) str2double(pby{1}{1}) ...
str2double(pbw{1}{1}) str2double(pbh{1}{1})];
% get coordinates representing the curve
S = loadsvg(fname,coarseness,false);
x = S{1}(:,1); % assuming the first path is the correct one
y = S{1}(:,2);
% if there are multiple paths you want to extract
% you'll need to do do the rescaling, etc for each element of S
% rescale to fit data range
x = xrange(1) + diff(xrange)*(x-pbrect(1))/pbrect(3);
y = yrange(1) + diff(yrange)*(pbrect(4) - (y-pbrect(2)))/pbrect(4);
% get rid of nonunique points
[x,idx,~] = unique(x);
y = y(idx);
% plot
plot(x,y); grid on; hold on
xlim(xrange)
ylim(yrange)
At this point, x and y will be relatively finely sampled. If you want to resample the curve on a coarser abcissa, you can use interp1().

その他の回答 (1 件)

Image Analyst
Image Analyst 2022 年 6 月 14 日
Lots of File Exchange submissions on digitizing a graph:

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