how to return indices?

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Lilya
Lilya 2022 年 6 月 12 日
コメント済み: Lilya 2022 年 6 月 12 日
Hi,
I have a 3 dimensional data matrix (72*45*2109), and I need to extract all data less than 15. the final output should be a 3d matrix
I used the following lines, but the result is a vector. The point is to return the indices to have 3d matrix.
Any help would be greatly appreciated.
[r,c,v] = ind2sub(size(data),find(data >= 15));
l = data(sub2ind(size(data),r,c,v));
  2 件のコメント
DGM
DGM 2022 年 6 月 12 日
編集済み: DGM 2022 年 6 月 12 日
You get a vector, because those are the indices of elements that you wanted -- only the indices you wanted.
Arrays need to be rectangular, without holes.
With that restriction, you'll have to decide what you want to fill all the area where there are elements you didn't want. It could be zero, NaN, etc. It's up to you and what the subequent code can accept without causing errors, since neither zero nor NaN are valid indices.
Lilya
Lilya 2022 年 6 月 12 日
thanks for your comment
I've created an output nan matrix with the same dimension (72*45*2109), but all the output (r,c,v) are vectros as well
I don't know how to put them back in the output matrix

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Dyuman Joshi
Dyuman Joshi 2022 年 6 月 12 日
Based on your comment -
%random data
y=randi(30,2,3,4)
y =
y(:,:,1) = 7 17 10 24 11 14 y(:,:,2) = 3 2 6 13 17 1 y(:,:,3) = 26 3 14 26 27 3 y(:,:,4) = 7 5 4 3 7 26
z=NaN(2,3,4);
z(y<15)=y(y<15)
z =
z(:,:,1) = 7 NaN 10 NaN 11 14 z(:,:,2) = 3 2 6 13 NaN 1 z(:,:,3) = NaN 3 14 NaN NaN 3 z(:,:,4) = 7 5 4 3 7 NaN
  1 件のコメント
Lilya
Lilya 2022 年 6 月 12 日
Thank you very much!!
perfectly worked.

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