Solving the linear equation

2 ビュー (過去 30 日間)
Salad Box
Salad Box 2022 年 6 月 7 日
回答済み: Torsten 2022 年 6 月 7 日
Hi,
For a simple explanation, an example is 21 = m x 7. m = 21/7 = 3. If I use the m I obtained to time 7, it should be equal to 21.
But above is just numbers, not matrix.
For solving similar problem on matrix, I would like to do a linear conversion from one matrix (P) to another (T).
My equation is T = MP, while T and P are both 3 by 24 matrices. I need to work out M.
My understanding is that M = T/P and M is a 3 x 3 matrix.
But why after I obtained M, I use M*P, it doesn't equal to T anymore. Why is that?
  1 件のコメント
Ranjan Sonalkar
Ranjan Sonalkar 2022 年 6 月 7 日
I would reframe the equation as y = Ax, where y contains the 9 terms of T, x contains the 9 unknowns from M and A would be the reformatted T. Then it is a least-squares solution.

サインインしてコメントする。

採用された回答

Matt J
Matt J 2022 年 6 月 7 日
編集済み: Matt J 2022 年 6 月 7 日
Because you have 72 equations and only 9 unknowns. The system is over-determined.

その他の回答 (1 件)

Torsten
Torsten 2022 年 6 月 7 日
M = T*P.'*inv(P*P.')
is the least-squares solution.
But you cannot expect that T=M*P is exactly satisfied.

カテゴリ

Help Center および File ExchangeStability Analysis についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by