Find all unique values and replace it with new values

I have a vector with values
v = [0.23; 0.1; 0.33; 0.23 ; 0.33; 0.6; 0.6; 0.4];
I would like to find the unique values and replace the vector with numbers from 1, like
newV = [1; 2; 3; 1 ; 3; 4; 4; 5];

 採用された回答

Walter Roberson
Walter Roberson 2022 年 6 月 6 日

2 投票

findgroups()
But since you are using floating point numbers you really should use the third output of uniquetol() instead

4 件のコメント

Elysi Cochin
Elysi Cochin 2022 年 6 月 6 日
But since you are using floating point numbers you really should use the third output of uniquetol() instead
Sir, but why? unique and findgroups also give the result. What is the reason?
Walter Roberson
Walter Roberson 2022 年 6 月 6 日
編集済み: Walter Roberson 2022 年 6 月 6 日
Are you 100% positive that the second 0.23 will be bit-for-bit identical to the first one? Are you assigning the initial value to an variable and then copying it to different locations in the array? Because if there is the slightest difference in how they are created, they might be different.
4.9/10 - 0.49 = 5.5511e-17
Elysi Cochin
Elysi Cochin 2022 年 6 月 7 日
okay sir will consider that
Image Analyst
Image Analyst 2022 年 6 月 7 日
@Elysi Cochin I'm pretty sure you've seen the FAQ on this before but here it is again:

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その他の回答 (2 件)

KSSV
KSSV 2022 年 6 月 6 日

2 投票

v = [0.23; 0.1; 0.33; 0.23 ; 0.33; 0.6; 0.6; 0.4];
[c,ia,newV] = unique(v,'stable') ;
newV
newV = 8×1
1 2 3 1 3 4 4 5
Image Analyst
Image Analyst 2022 年 6 月 6 日

2 投票

Will this do:
v = [0.23; 0.1; 0.33; 0.23 ; 0.33; 0.6; 0.6; 0.4];
% newV = [1; 2; 3; 1 ; 3; 4; 4; 5];
[g, Tid] = findgroups(v)
g = 8×1
2 1 3 2 3 5 5 4
Tid = 5×1
0.1000 0.2300 0.3300 0.4000 0.6000
I know it doesn't match your desired but it's easy and maybe you don't need that exact order. If you need that exact order, can you explain why you need that order? (And don't jsut say I need it because I need it.)

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