How to use feather, quiver or stickplot for wind direction timeseries?

I need to do a plot like the figure but I don´t know which function plot to use. I have the wind direction in degrees and the wind speed in m/s. I want the xtick to be the date.

Thank you!

Answer 1

[Sai Pavan]

Hi Daniela,

I understand that you are trying to figure out which of the plot functions to use to plot the wind direction timeseries data in the format shown in the uploaded figure.

The “quiver” function can be used to plot the wind direction timeseries data so that the arrows originate from x-axis and creates quiver plots, which represent wind direction as arrows with lengths and directions proportional to wind speed and direction respectively. The X-axis represents the time and “xtick" can be set to date.

Please refer to the below documentation to know more about the “quiver” function:

https://www.mathworks.com/help/matlab/ref/quiver.html

Here's a reference code to plot the quiver plot of wind speed and direction data:

figure;
quiver(time, zeros(size(time)), windSpeed.*sind(windDirection), windSpeed.*cosd(windDirection)); 
title('Quiver Plot'); 
xlabel('Time'); 
ylabel('Wind Direction (degrees)'); 
axis tight; 

Hope it helps.

Regards,

Sai Pavan

[indika kathaluwa weligamage]

Hi Sai Pavan

Thank your answer. It is very very important for me too.

I tried but result not like the expected. (As requested in first question)

Could you please futher explain.

A set of ample data and my cord are attached herewith for your kind consideration.

Thanks,INDIKA

load jan.txt;

windDirection=jan(:,5);

windSpeed=jan(:,4);

time=jan(:,1);jan(:,2);jan(:,3);

%time=power_2022(:,1:3);%

figure;

quiver(time, zeros(size(time)), windSpeed.*sind(windDirection), windSpeed.*cosd(windDirection));

2022 1 1 58.5 4.39

2022 1 2 62.81 5.99

2022 1 3 69.56 5.83

2022 1 4 67 4.88

2022 1 5 110.44 2.09

2022 1 6 78.25 3.9

2022 1 7 69.69 4.26

2022 1 8 40.31 3.02

2022 1 9 58.81 3.69

2022 1 10 118.62 2.11

2022 1 11 125.12 2.11

2022 1 12 163.56 2.31

2022 1 13 197.88 2.56

2022 1 14 126.88 1.77

2022 1 15 75.06 1.72

2022 1 16 55.69 4.48

2022 1 17 62.5 5.11

2022 1 18 61.44 4.14

2022 1 19 44.81 4.49

2022 1 20 130.12 2.73

2022 1 21 255.25 1.59

2022 1 22 216 1.54

2022 1 23 141.62 1.45

2022 1 24 120.94 1.8

2022 1 25 93.25 2.52

2022 1 26 60.5 2.71

2022 1 27 49.88 3.48

2022 1 28 76.25 3.53

2022 1 29 108.25 3.03

2022 1 30 90.44 3.49

2022 1 31 76.75 4.6

Answer 2

[Madmad]

A bit late but had the same issue, figured it out so if someone needs a code to do it:

% Number of months (5 years)
numMonths = 60;
u = randn(numMonths, 1) * 10; 
v = randn(numMonths, 1) * 10; 
windSpeed = sqrt(u.^2 + v.^2);
years = repmat(2002:2006, 1, 12);
yearIndices = 1:12:numMonths;
figure;
hold on;
for i = 1:numMonths
    xStart = i; 
    yStart = 0; 
    uComponent = u(i); 
    vComponent = v(i);
    quiver(xStart, yStart, uComponent, vComponent, 0, 'k', 'LineWidth', 2, 'MaxHeadSize', 2, 'AutoScale', 'off');
end
yLimits = [-max(windSpeed), max(windSpeed)];
yTicks = -10:2:10; 
for y = yTicks
    if y >= yLimits(1) && y <= yLimits(2)
        yline(y, '--k');
    end
end
yline(0, '-k');
set(gca, 'YTick', yTicks);
set(gca, 'XTick', yearIndices);
set(gca, 'XTickLabel', arrayfun(@(x) num2str(x), ...
    years(yearIndices), 'UniformOutput', false));
xlabel('Year');
ylabel('Wind Speed (m/s)');
title('Monthly Wind Speed for 5 Years');
grid on;
hold off;