Growing eye matrix as per the size of eye

I have an eye matrix of size eye(3). I need to increase the size of matrix as below so that eye matrix has to repeat 2 times then 3 times. Can anyone help

Answer 1

[Chunru]

a = tril(repmat(eye(3), [3, 3]))

a = 9×9

1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1

[Babu Thomas]

Thank you

Answer 2

[DGM]

There are a number of ways, but this is what I'd do:

A = toeplitz([1 0 0 1 0 0 1 0 0],[1 0 0 0 0 0 0 0 0])

A = 9×9

1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1

[Babu Thomas]

Thank you

Answer 3

[Bruno Luong]

tril(repmat(eye(3),3))

ans = 9×9

1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1

[Babu Thomas]

Thank you

Answer 4

[KSSV]

REad about diag

I = diag(repelem(1,1,9))+diag(repelem(1,1,6),-3)+diag(repelem(1,1,3),-6)

I = 9×9

1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 0 1 0 0 1

[Babu Thomas]

Thank you