"Column Vector" XTick labels
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Consider the following plot:
plot(0:2,2-(0:2),'*'),xticks([0 1 2]),xticklabels({'(0,2)','(1,1}','(2,0)'})
I want to keep the "plot" as is, just change the labeling for the x axis ticks., so that each xtick label would be a column vector instead of a pair in parentheses. For instance,
0 1 2
2 1 0
instead of
(0,2) (1,1) (2,0)
Is this possible?
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採用された回答
Voss
2022 年 5 月 28 日
編集済み: Voss
2022 年 5 月 28 日
plot(0:2,2-(0:2),'*')
xticks([0 1 2])
xticklabels(sprintfc('%d\\newline%d',[0 2 1 1 2 0]))
5 件のコメント
Voss
2022 年 5 月 28 日
xticks() % leaving xticks at its default, for the time being
xtl = sprintfc('%d\n%d',[0 2 1 1 2 0])
xticklabels(xtl)
Then I remembered another answer I had seen recently, about emboldening a single xticklabel (an answer of yours, incidentally):
There, sending \bf to the TeX interpreter solved the problem, so I tried to do the same thing here but with a line break. I had to look up how to make a line break in TeX, and what I found was this question:
which suggested that \newline was the way to go, so I tried it out and it seemed to work.
dpb
2022 年 5 月 30 日
I guess I had never looked that up before, or if had done in the past, had certainly forgotten it.
The undocumented sprintfc is handy, too; that replaces the functionality I got with the loop and explicit cast. I hadn't stumbled over it before, either...
その他の回答 (1 件)
dpb
2022 年 5 月 28 日
編集済み: dpb
2022 年 5 月 28 日
I don't think so with the tick labels(*), but you can write them with text as
v1=[0:2];v2=[2:-1:0];
for i=1:3
xtl(i)=cellstr(sprintf('%d\n%d',v1(i),v2(i)));
end
xticklabels([])
text(xticks,repmat(-0.02,1,3),xtl,'VerticalAlignment',"top")
(*) When try to write string with embedded \n, the internals of xticklabels converts each to another string element so you end up with it thinking 2X the labels than number of ticks.
2 件のコメント
dpb
2022 年 5 月 28 日
Yeah, it is "magic" number as shown -- because the default coordinates for text are in 'data' units. This can be set to be 'normalized' which are the units of the axes and then a fixed offset from the lower position number is the invariant way to place.
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