Is it possible to bin/discretize multidimensional matrices?
4 ビュー (過去 30 日間)
古いコメントを表示
alberto tonizzo
2022 年 5 月 26 日
コメント済み: alberto tonizzo
2022 年 5 月 26 日
I have a 5D matrix that I want to bin according to a vector that has the same length as the first dimension of the matrix.
Thank you!
0 件のコメント
採用された回答
Walter Roberson
2022 年 5 月 26 日
bins = discretize(TheMatrix, Vector_of_Breakpoints);
It does not matter how many entries are in Vector_of_Breakpoints as long as there are at least two values and the vector is sorted.
The result would be a matrix the same size as TheMatrix.
If any values are less than Vector_of_Breakpoints(1) or greater than Vector_Of_Breakpoints(end) then the corresponding output will be 0.
Note that by default the maximum bin number will be length(Vector_of_Breakpoints)-1 with the values exactly equal to Vector_of_Breakpoints(end) being placed together with the previous bin. There are options to change how the boundaries work.
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Creating and Concatenating Matrices についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!