Order Points for plotting

I have the coordinates of the above two shapes imported from a CAD software, however when I plot the shape the points are not in order. Is there a method to order the coordinates so that points on the perimeter of the shape that are side by side are next to each other in the matrix.
If there is any mathematical method that would help me, I am willing to understand it and code it myself. Thank you

6 件のコメント

KSSV
KSSV 2022 年 5 月 24 日
When you extract it from CAD, you can extract into a stl file right?
Attach your data, there are some methods which can be tried. Read about boundary
Ahmed Abdulla
Ahmed Abdulla 2022 年 5 月 24 日
I attached the sample data for the anchor shape, i tried boundary but for some reason it skips some points ans changes the shape :(
Ahmed Abdulla
Ahmed Abdulla 2022 年 5 月 24 日
Thanks @KSSV, This is the result of using boundary with a shrink factor of 1, however a few points get ignored. Is there a way of using all points?
Walter Roberson
Walter Roberson 2022 年 5 月 24 日
use a different shrink factor?
Ahmed Abdulla
Ahmed Abdulla 2022 年 5 月 24 日
@Walter Roberson Here I am using a shrink factor of 1 which is the highest I can go :(
DGM
DGM 2025 年 7 月 10 日
I can't imagine there exists any CAD software which represents polygons (internally or externally) using no information other than a list of unordered vertices. Depending on the file, the object might not be represented as a simple polygon, but at some point, this became a polygon.
That's not to say that these vertices have no order. They're sorted by their x-value -- which is precisely what would happen to the vertex list if you imported an STL using FEX #51200, or if you imported it using any other FEX decoder and then used unique() to prune the vertex list without using the 'stable' flag. These vertices would never appear in an STL file in this order. Granted, I'm guessing it's an STL, but all we could ever do is guess what the file was.
My point is that if you want connectivity information, it's probably worth trying to go back to the source, instead of trying to inaccurately and inconsistently regenerate information that (at some point) you already had.

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回答 (1 件)

KSSV
KSSV 2022 年 5 月 24 日

0 投票

load('A.mat') ;
x = A(:,1) ; y = A(:,2) ;
n = length(x) ;
iwant = zeros(n,2) ;
i = 1 ;
iwant(i,:) = [x(i) y(i)] ;
x(i) = [] ; y(i) = [] ;
while ~isempty(x)
i = i+1;
idx = knnsearch([x y],iwant(i-1,:));
iwant(i,:) = [x(idx) y(idx)] ;
x(idx) = [] ; y(idx)= [];
end
iwant(end+1,:) = iwant(1,:) ;
plot(iwant(:,1),iwant(:,2))

3 件のコメント

Ahmed Abdulla
Ahmed Abdulla 2022 年 5 月 24 日
Thank you @KSSV for your amazing effort. If you notice in the bottom left there is distorion where the code miss chose the points. I tried with several of my shapes and the problem persists :(
KSSV
KSSV 2022 年 5 月 24 日
編集済み: KSSV 2022 年 5 月 24 日
Lets randomize the points and run the code.
load('A.mat') ;
x = A(:,1) ; y = A(:,2) ;
n = length(x) ;
idx = randperm(n,n) ;
x = x(idx) ; y = y(idx) ;
iwant = zeros(n,2) ;
i = 1 ;
iwant(i,:) = [x(i) y(i)] ;
x(i) = [] ; y(i) = [] ;
while ~isempty(x)
i = i+1;
idx = knnsearch([x y],iwant(i-1,:));
iwant(i,:) = [x(idx) y(idx)] ;
x(idx) = [] ; y(idx)= [];
end
iwant(end+1,:) = iwant(1,:) ;
plot(iwant(:,1),iwant(:,2))
Ahmed Abdulla
Ahmed Abdulla 2022 年 5 月 24 日
Thank you @KSSV for your efforts I really appreciate it. Unfortunately this doesnt work every time and I am trying to make a generalised function that will work for any shape and at all times

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2022 年 5 月 24 日

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DGM
2025 年 7 月 10 日

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