# Avoiding for loop for 1d-intepolation

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Omid Sharifi Sedeh 2022 年 5 月 21 日
コメント済み: Omid Sharifi Sedeh 2022 年 5 月 22 日
Hi,
Generally, I try to avoid for loops. Is there any way of avoiding the following for loop?
for ii=1:length(alpha)
result(ii) = interp1(Eng_mat,res(:,ii),alpha(ii),'linear', 'extrap');
end
Dimension of the matrices: Eng_mat is 4000*1, res is 4000*10, alpha is 10*1
In principle, I need to use interpolation for each element of alpha according to ii'th coloumn of res.
I appreciate it if someone could help me with this.
Thanks

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### 回答 (1 件)

Image Analyst 2022 年 5 月 21 日
I don't see a simpler way off the top of my head. You have only 10 iterations so I wouldn't worry about it. Ten iterations of a for loop will probably be faster than any other way you'd do it. If you had tens of millions of iterations then maybe it would be time to worry about a for loop, but for 10? Don't worry about it.
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Omid Sharifi Sedeh 2022 年 5 月 22 日
Well, I think there is a misunderstanding here. The actual code is way more complicated. What I meant is that this 'for' loop will be called 1 million times and not only one time over 10 iterations. The interpolation speed, on the other hand, depends on the dimensions of Eng_mat and res. If I increase it more, the runtime will be affected considerably.
Anyways, I used a trick and it seems to be working. I noticed that the desired results are stored in the first row of 'result':
result = interp1(Eng_mat,res,alpha,'linear', 'extrap');
result=result(1,:);
Thanks

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