integral2 with parameters
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i am trying to solve this king of integral using matlab how do i do it?1 件のコメント
The integral does not exist.
In the limits from a to b (0<=a<b<R), it equals
log(sqrt((R^2-a^2)/(R^2-b^2)))
回答 (1 件)
Charles Barthelmebs
2022 年 5 月 20 日
If you search the analytical solution you can try this:
syms r;
f = r/(R^2-r^2)
int(f,x,0,R)
but for numerical, you can use
integral(function,Xmin,Xmax)
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