How can I reshape a matrix this way
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Jaime De La Mota Sanchis
2022 年 5 月 5 日
コメント済み: Jaime De La Mota Sanchis
2022 年 5 月 5 日
I have a matrix defined as
a=[-0.26,0.23,0.033,0.1,-0.39,0.30;0.30,-0.39,0.10,-0.26,0.03,0.23;-0.03,-0.13,0.16,0.33,-0.16,-0.16]
and I need to reshape it so it looks like
b=[-0.26,0.23,0.033;0.1,-0.39,0.30;0.30,-0.39,0.10;-0.26,0.03,0.23;-0.03,-0.13,0.16;0.33,-0.16,-0.16]'
I have tried using reshape, but nothing comes to my mind.
I have tried, but as you can see, this is not what I am looking for.
b2=reshape(a, 18, 1);
b3=reshape(b2, 6,3);
bAttempt=b3';
Can someone please help me?
Best regards.
Jaime.
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採用された回答
James Tursa
2022 年 5 月 5 日
a=[-0.26,0.23,0.033,0.1,-0.39,0.30;0.30,-0.39,0.10,-0.26,0.03,0.23;-0.03,-0.13,0.16,0.33,-0.16,-0.16]
b=[-0.26,0.23,0.033;0.1,-0.39,0.30;0.30,-0.39,0.10;-0.26,0.03,0.23;-0.03,-0.13,0.16;0.33,-0.16,-0.16]'
c = reshape(a',3,[])
その他の回答 (1 件)
Umur Ayberk
2022 年 5 月 5 日
If I'm not mistaken, you can achieve that result by reshaping the transpose of a.
a=[-0.26,0.23,0.033,0.1,-0.39,0.30;0.30,-0.39,0.10,-0.26,0.03,0.23;-0.03,-0.13,0.16,0.33,-0.16,-0.16]
at = a';
c = reshape(at(:),size(a,1),size(a,2))
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