Unit step function - Explain this 10 line code?

1 回表示 (過去 30 日間)
deltanabla
deltanabla 2015 年 1 月 20 日
i Folks,
I have difficulty understanding what is happening with this code. It is meant to simulate the unit step function
(t-a)=1 for t>a and (t-a)=0 for t<a
The resulting output is vector of 0's and 1's when its inside another function. However, when I extract the function for simplicity to show here, it just calculates a bunch of 1's. In either case, i dont understand the 3rd last line...
function y = h(t)
t = linspace(0,36*pi,2^15)';
y = zeros(size(t));
for k = 1:length(t)
if t(k)>0
y(k) = 1;
else
y(k) = 0;
end
end
function y = U(t,i,N,Tc)
y = 0;
N=1;
Tc=6.28;
for i=1:N
for n=1:100
y = y + h(t-(((n-1)*N+i-1)/N)*Tc) - h(t-(((n-1)*N+i)/N)*Tc);
end
end
Thanks

回答 (0 件)

カテゴリ

Help Center および File ExchangeMATLAB についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by