How to slice an array across multiple dimensions with two limit arrays?
10 ビュー (過去 30 日間)
古いコメントを表示
I'm interested in taking an arbitrary N-dimensional array, and two 1xN vectors, and using the two vectors as start/stop indices to slice the array, but I'm not sure how. Here's what I mean:
Let X be an N-dimensional array.
Let A and B be 1xN vectors like so:
A=[a1, a2, ..., aN]
B=[b1, b2, ..., bN]
How do I slice X such that I get this:
Y = X(a1:b1, a2:b2, ..., aN:bN)
I tried X(A:B), but that doesn't work - not even sure what that operation is doing, but it isn't doing what I want. I tried to think of some way to do it with logical indexing, but nothing simple came to mind. I could slice the array one dimension at a time in a loop, but it seems like there must be a one-liner. Thanks!
0 件のコメント
採用された回答
Bruno Luong
2022 年 4 月 22 日
編集済み: Bruno Luong
2022 年 4 月 22 日
This should work
X=rand(6,6,6);
A=[1 2 3]; B=[6 5 4];
cidx = arrayfun(@(i1,i2) i1:i2, A, B, 'unif', 0);
Y = X(cidx{:})
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Creating and Concatenating Matrices についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!