create vector in for loop and then need to store vector in a matrix one after another

I want to create a code in double for loop shown below. When vector "v" creates in first run then its store values but when internal "for loop" increaed the value of b by 0.1 then previous values in vector v replaced. I need both values and i don,t understand how i get?

Every time value changed i need. I want to store values in a matrix means first run stores in first row, then value increment in internal for loop then this valus agiain stored ina matrix and so on. at the end i need all combinations in a matrix.

Can anyone give me a suitable suggestion? thanks in advance

clear all

for a=1:0.1:2

k1=a

for b=1:0.1:2

k2=b;

v=[k1 k2]

newtable=array2table(v)

end

end

[Rik]

You aren't using any indexing. I suggest you have a look at the relevant chapter of the Onramp tutorial.

Answer 1

[Voss]

Is this what you mean?

clear all
v = [];
for a=1:0.1:2
    k1=a;
    for b=1:0.1:2
        k2=b;
        v(end+1,:)=[k1 k2];
    end
end
disp(v);

    1.0000    1.0000
    1.0000    1.1000
    1.0000    1.2000
    1.0000    1.3000
    1.0000    1.4000
    1.0000    1.5000
    1.0000    1.6000
    1.0000    1.7000
    1.0000    1.8000
    1.0000    1.9000
    1.0000    2.0000
    1.1000    1.0000
    1.1000    1.1000
    1.1000    1.2000
    1.1000    1.3000
    1.1000    1.4000
    1.1000    1.5000
    1.1000    1.6000
    1.1000    1.7000
    1.1000    1.8000
    1.1000    1.9000
    1.1000    2.0000
    1.2000    1.0000
    1.2000    1.1000
    1.2000    1.2000
    1.2000    1.3000
    1.2000    1.4000
    1.2000    1.5000
    1.2000    1.6000
    1.2000    1.7000
    1.2000    1.8000
    1.2000    1.9000
    1.2000    2.0000
    1.3000    1.0000
    1.3000    1.1000
    1.3000    1.2000
    1.3000    1.3000
    1.3000    1.4000
    1.3000    1.5000
    1.3000    1.6000
    1.3000    1.7000
    1.3000    1.8000
    1.3000    1.9000
    1.3000    2.0000
    1.4000    1.0000
    1.4000    1.1000
    1.4000    1.2000
    1.4000    1.3000
    1.4000    1.4000
    1.4000    1.5000
    1.4000    1.6000
    1.4000    1.7000
    1.4000    1.8000
    1.4000    1.9000
    1.4000    2.0000
    1.5000    1.0000
    1.5000    1.1000
    1.5000    1.2000
    1.5000    1.3000
    1.5000    1.4000
    1.5000    1.5000
    1.5000    1.6000
    1.5000    1.7000
    1.5000    1.8000
    1.5000    1.9000
    1.5000    2.0000
    1.6000    1.0000
    1.6000    1.1000
    1.6000    1.2000
    1.6000    1.3000
    1.6000    1.4000
    1.6000    1.5000
    1.6000    1.6000
    1.6000    1.7000
    1.6000    1.8000
    1.6000    1.9000
    1.6000    2.0000
    1.7000    1.0000
    1.7000    1.1000
    1.7000    1.2000
    1.7000    1.3000
    1.7000    1.4000
    1.7000    1.5000
    1.7000    1.6000
    1.7000    1.7000
    1.7000    1.8000
    1.7000    1.9000
    1.7000    2.0000
    1.8000    1.0000
    1.8000    1.1000
    1.8000    1.2000
    1.8000    1.3000
    1.8000    1.4000
    1.8000    1.5000
    1.8000    1.6000
    1.8000    1.7000
    1.8000    1.8000
    1.8000    1.9000
    1.8000    2.0000
    1.9000    1.0000
    1.9000    1.1000
    1.9000    1.2000
    1.9000    1.3000
    1.9000    1.4000
    1.9000    1.5000
    1.9000    1.6000
    1.9000    1.7000
    1.9000    1.8000
    1.9000    1.9000
    1.9000    2.0000
    2.0000    1.0000
    2.0000    1.1000
    2.0000    1.2000
    2.0000    1.3000
    2.0000    1.4000
    2.0000    1.5000
    2.0000    1.6000
    2.0000    1.7000
    2.0000    1.8000
    2.0000    1.9000
    2.0000    2.0000

[Muhammad Asad]

Thanks for your answer. May I new for indexing etc. Thats why facing some difficulties.

My little query is also about to add third row in disp (v). After k2=b i need to add a command that run simulink model and give back returned a variable as a result. Let k3= 4 but its value vary after every time code execute or every time when "for" loop runs

I try to write k3=4 in above/below mentioned code but when i run i get different result. in your code

clear all

v = [];

for a=1:0.1:2

k1=a;

for b=1:0.1:2

k2=b;

v(end+1.:)=[k1 k2];

end

end

disp(v);

[Voss]

Can you show the code where you are using k3?

[Muhammad Asad]

Now, I try to use k3 and it is working. But i really thanks to you and all of the experts that try to resolve my issue.

If you not mind then please explain a little about this command v(end+1,:)=[k1 k2 k3] .

Particularly v(end+1,:) means.....

One last thing is that I want to run coding and during coding i need to refered simulink model. i want to run a simulink block model becuase when it runs it give me the value of k3. I used command load ( ) and in parentheses i write name of simulink block model but not successful. if you just tell me that which command i used for this. i really appreciate to you.

updated code given below.

clear all

v = [];

for a=1:0.1:2

k1=a;

for b=1:0.1:2

k2=b;

k3=3;

v(end+1,:)=[k1 k2 k3];

end

end

disp(v);

[Voss]

The end keyword in an indexing expression refers to the last index of the dimension it's used. So v(end,:) refers to the last row of v, and v(end+1,:) would refer to the row one beyond the last row. In this expression:

v(end+1,:)=[k1 k2 k3] 

[k1 k2 k3] is assigned to the row one beyond the last row of v, so the effect is to add a new row to the end of v containing [k1 k2 k3].

About the Simulink block question, I don't know. I've never used Simulink. Maybe ask a new question about it and post the latest version of your code in the new question.

[Rik]

Some comments:

You should avoid clear all. You never actually need it. Using clear or clearvars instead is almost always enough for a debugging script. For actual use, you should be using a function, which will always start out with a clean workspace.

You should try to determine the size of your array based on your variables. That way you can pre-allocate the entire array, which avoids data copying when extending the array, and will also give you an early warning if there are memory issues.

I strongly suggest to do the Onramp tutorial. It is really worth the investment to learn the tool you're using.