Fast function application
1 回表示 (過去 30 日間)
古いコメントを表示
Hi,
Let a be n-dimensional vector, B n-by-n dimensional matrix, f(a, b) - binary function that operates on two vectors, and returns scalar as a result. Is there fast way (no-loops) to implement application of this function to vector a and every column of matrix B? More precisely forall_j r(j) = f(a, B(:, j))?
採用された回答
Walter Roberson
2011 年 9 月 29 日
These days, "no loops" is not necessary any faster.
You can use
arrayfun(@(K) f(a,B(:,K)), 1:size(B,2))
but that will probably not be any faster than a loop.
0 件のコメント
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Loops and Conditional Statements についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!