Is there a way to check each index of a matrix against each index of another smaller matrix?

Is there a way to check each index of a matrix against each index of another smaller matrix? I am trying to create a code that will check the index of one matrix, A, and compare it to another matrix, B. I want to find a row vector in A where none of the index in that row are equal to any of the index in B. I was thinking of using a for loop and somehow incorporating the find() function, but I am not sure where to start. Any tips would be appreciated.

Answer 1

[Voss]

% a matrix:
A = magic(5)

A = 5×5

17 24 1 8 15 23 5 7 14 16 4 6 13 20 22 10 12 19 21 3 11 18 25 2 9

% a smaller matrix:
B = [1 15 6; 20 12 21; 25 2 9]

B = 3×3

1 15 6 20 12 21 25 2 9

% index(es) of row(s) of A that have no elements in B:
find(~any(ismember(A,B),2))

ans = 2

% breaking that expression down a little bit:
ismember(A,B)

ans = 5×5 logical array
   0   0   1   0   1
   0   0   0   0   0
   0   1   0   1   0
   0   1   0   1   0
   0   0   1   1   1

any(ismember(A,B),2)

ans = 5×1 logical array
   1
   0
   1
   1
   1

~any(ismember(A,B),2)

ans = 5×1 logical array
   0
   1
   0
   0
   0