Newton's iteration

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Diyora Zayitova
Diyora Zayitova 2011 年 9 月 29 日
Consider the following Newton iteration formula x n+1 =(1/3) (2xn-R/xn^2) , Does it converge for x0 does not equal 0? if so, to what values?
  3 件のコメント
Walter Roberson
Walter Roberson 2011 年 9 月 29 日
This posting too needs proper bracketing.
Jan
Jan 2011 年 9 月 29 日
@Diyora: You've posted 3 homework questions without showing any effort. This is not a good start in a forum. We are not an answering machine.
If you show, what you have done so far and ask for specific problems, it is more liekly that other users spend time for helping you.

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回答 (1 件)

William
William 2011 年 9 月 29 日
Do you have the symbolic toolbox? If so syms x n
(Formula)

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