A figure drawn in a function disappears after exiting the function.

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Ranjan Sonalkar
Ranjan Sonalkar 2015 年 1 月 13 日
コメント済み: Image Analyst 2015 年 1 月 13 日
I call a function multiple times with a different integer argument, 'month'. I open up a new figure each time within the function - 'figure(month)'. However, the figures do not survive when the program ends. I have tried calling the function with a new figurehandle and opened the figure within the function with that figurehandle. But, the figure still does not survive. Even if I call the function once, the figure does not survive. How can I draw a figure within a function and have it available when the program ends>
In the calling program, I have "figureHandle=figure(month)". I pass the figureHandle as an argument to the function and within the function I initiate the figure by "figure(figureHandle)". What am I doing wrong?

回答 (1 件)

Image Analyst
Image Analyst 2015 年 1 月 13 日
Are you assigning the figure() output to a handle, which will be a local variable? When the function exits, that local variable will get destroyed/deleted and so your figure window will probably go away also.
  2 件のコメント
Image Analyst
Image Analyst 2015 年 1 月 13 日
That explanation does not explain what's going wrong. We're going to need your code. Strip it down to the essentials and attach it.

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