calculate the number of odd fence values instead of printing them

Sample Output:

Given A = [ 5, 4, 6, 7, 3 ; 1, 2, 3, 4, 5 ; 5, 6, 4, 2, 4 ; 4, 5, 3, 2, 1]

% output demo

There are 9 odd values in the fence.

% This is my code

% given a matrix

A = [5,4,6,7,3;1,2,3,4,5;5,6,4,2,4;4,5,3,2,1];

% Get the number of rows and columns

[m,n] = size(A);

odd = 0;

for i = 1:m % number of rows

for j = 1:n % number of column

if (mod(A(i),2)~= 0) % if the element is not equal to zero, this is odd values

odd = odd + 1;

end

end

end

fprintf("There are %d odd values in the fence",odd);

There are 9 odd values

but in my code, it is shows There are 15 odd values in the fence.

How to improve this code?

[Image Analyst]

What is your definition of fence? Do you mean matrix?

Answer 1

[Voss]

if (mod(A(i,j),2)~= 0)

Use A(i,j) instead of A(i)

[Shuoze Xu]

Ok, it works.

Thank you.

[Voss]

You're welcome!

[Image Analyst]

And why do you say there are 9 values? My code below shows there are 10 values. Why do we disagree? Which one did I count that you say should not be counted?

[Shuoze Xu]

There are 9 odd values showed on the pdf, I think it may a mistake

Answer 2

[Image Analyst]

A = [ 5, 4, 6, 7, 3 ; 1, 2, 3, 4, 5 ; 5, 6, 4, 2, 4 ; 4, 5, 3, 2, 1] 

A = 4×5

5 4 6 7 3 1 2 3 4 5 5 6 4 2 4 4 5 3 2 1

numOddNumbers = nnz(rem(A, 2))

numOddNumbers = 10