How to get only those output values which lie under a given curve!

1 回表示 (過去 30 日間)
am
am 2014 年 12 月 24 日
回答済み: Shoaibur Rahman 2014 年 12 月 24 日
Hi everyone, I have a graph with tabulated values (x1-xn, y1-yn and z1-zn). I used interpolation to get required values of 'Z' w.r.t x and y. However i also need to use only those values of Z which lie under a given line ( limiting curve ) having four coordinates ( as mentioned in fig). I don't have any equation for this line then how can i make sure my output value always remain under this given curve or satisfy this condition!
TiA for all the good work you do!
regards

採用された回答

Shoaibur Rahman
Shoaibur Rahman 2014 年 12 月 24 日
Perhaps, you unconsciously mistyped the x coordinate of third point. I use 3800 instead of 2100, but use what the actual value is. Also, I use random Z data here for test purposes.
x = 1000:4500;
z = 11+randn(1,length(x)); % use the data that you got
plot(x,z,'om'), hold on
x1 = 1000:2100;
y1 = 8+(8-13.2)/(1000-2100)*(x1-1000); % first boundary, straight line equation
z1 = z(1:length(y1)); % z values in the given range x1
z1(z1 >= y1) = NaN; % discard z values that are above the boundary
plot(x1,y1,'r'), plot(x1,z1,'o','MarkerSize',12)
x2 = 2100:3800;
y2 = 13.2+(13.2-14.6)/(2100-3800)*(x2-2100); % second boundary
z2 = z(length(y1)+1:length(y1)+length(y2)); % z values in the given range x2
z2(z2 >= y2) = NaN; % discard z values that are above the boundary
plot(x2,y2,'r'), plot(x2,z2,'o','MarkerSize',12)
x3 = 3800:4500;
y3 = 14.6+(14.6-12)/(3800-4500)*(x3-3800); % third boundary
z3 = z(length(y1)+length(y2)-1:end); % remaining z values
z3(z3 >= y3) = NaN; % discard z values that are above the boundary
plot(x3,y3,'r'), plot(x3,z3,'o','MarkerSize',12)

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeInterpolation についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by