How to replace zeros in a vector with random segments of the same vector?
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I have a vector with 240000 data points. There are several, 72 elements long segments of zero values in that vector. Now I would like to replace these segments of zeros with random 72 elements long segments from the remaining non zero part of the vector.
Can you help me how can I do it?
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採用された回答
Image Analyst
2022 年 3 月 24 日
Try this:
% First we need to create the data since the original poster forgot to attach it for us.
% Make random vector with values in the 1-9 range.
v = randi(9, 1, 24000);
% Make 20 stretches of 72 zeros.
startingIndexes = sort(randi(length(v), 1, 20))
for k = 1 : length(startingIndexes)
v(startingIndexes(k) : startingIndexes(k) + 71) = 0;
end
% Now we have our vector and we can begin.
%---------------------------------------------------------------------------------
% First find out what the non-zero values are
% that we can use to plug the regions of zeros.
% tic; % Start timer
availableToUse = unique(nonzeros(v));
% Now plug the zeros with numbers randomly chosen from availableToUse
for k = 1 : length(v)
if v(k) == 0
% It's zero so replace it with a random number chosen from availableToUse.
randomIndex = randi(length(availableToUse), 1, 1);
v(k) = availableToUse(randomIndex);
end
end
% toc % End timer
Time to execute is 0.002 seconds (2 milliseconds).
その他の回答 (1 件)
Arif Hoq
2022 年 3 月 24 日
try this:
A=[1 2 3 0 0 0 4 5 0 0 0 0 0 0 0 0 8 9]'; % any matrix
B=A(A==0); % extract the number of 0
rdnumber=randi([10 20],size(A,2),numel(B)); % generating random number
A(A==0)=rdnumber % replace with random number
1 件のコメント
Image Analyst
2022 年 3 月 24 日
That is not using only the non-zero values to plug the zeros, like I do in my answer. You're including numbers not in the original vector.
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