symbolic matrix help converting
2 ビュー (過去 30 日間)
古いコメントを表示
syms j w C R h11 h12 h21 h22
%matrix i would like to solve ABCD=[1 (1/(j*w*C))+R; 0 1]
%formular to converting ABCD to h para
A=((h11*h22)-(h12*h21))/h21
B=-h11/h21
C=-h22/h21
D=-1/h21
ABCD=[A B;C D]
i have problem trying to get a matrix from the original matrix(ABCD=[1 (1/(j*w*C))+R; 0 1])
using the formular
A=((h11*h22)-(h12*h21))/h21
B=-h11/h21
C=-h22/h21
D=-1/h21
please help
0 件のコメント
回答 (1 件)
Star Strider
2022 年 3 月 22 日
One problem is that ‘C’ is being used to designate the capacitor, and also the ‘ABCD’ (2,1) element. Designating the capacitor as ‘Cc’ removes that ambiguity —
syms w Cc R h11 h12 h21 h22
%matrix i would like to solve ABCD=[1 (1/(j*w*Cc))+R; 0 1]
%formular to converting ABCD to h para
A=((h11*h22)-(h12*h21))/h21
B=-h11/h21
C=-h22/h21
D=-1/h21
ABCD=[A B;C D]
ABCD = simplify(ABCD, 500)
S = ABCD == [1 (1/(1j*w*Cc))+R; 0 1]
[h11 h12 h21 h22] = solve(S,[h11 h12 h21 h22])
I also removed ‘j’ and replaced it with the imaginary operator ‘1j’ (that now appears as i) for clarity.
.
0 件のコメント
参考
カテゴリ
Help Center および File Exchange で Numbers and Precision についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!