symbolic matrix help converting

syms j w C R h11 h12 h21 h22
%matrix i would like to solve ABCD=[1 (1/(j*w*C))+R; 0 1]
%formular to converting ABCD to h para
A=((h11*h22)-(h12*h21))/h21
B=-h11/h21
C=-h22/h21
D=-1/h21
ABCD=[A B;C D]
i have problem trying to get a matrix from the original matrix(ABCD=[1 (1/(j*w*C))+R; 0 1])
using the formular
A=((h11*h22)-(h12*h21))/h21
B=-h11/h21
C=-h22/h21
D=-1/h21
please help

回答 (1 件)

Star Strider
Star Strider 2022 年 3 月 22 日

0 投票

One problem is that ‘C’ is being used to designate the capacitor, and also the ‘ABCD’ (2,1) element. Designating the capacitor as ‘Cc’ removes that ambiguity —
syms w Cc R h11 h12 h21 h22
%matrix i would like to solve ABCD=[1 (1/(j*w*Cc))+R; 0 1]
%formular to converting ABCD to h para
A=((h11*h22)-(h12*h21))/h21
A = 
B=-h11/h21
B = 
C=-h22/h21
C = 
D=-1/h21
D = 
ABCD=[A B;C D]
ABCD = 
ABCD = simplify(ABCD, 500)
ABCD = 
S = ABCD == [1 (1/(1j*w*Cc))+R; 0 1]
S = 
[h11 h12 h21 h22] = solve(S,[h11 h12 h21 h22])
h11 = 
h12 = 
h21 = 
h22 = 
0
I also removed ‘j’ and replaced it with the imaginary operator ‘1j’ (that now appears as i) for clarity.
.

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2022 年 3 月 22 日

回答済み:

2022 年 3 月 22 日

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