Using movmean to calculate mean of first and last element in array

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sr9497
sr9497 2022 年 3 月 22 日
コメント済み: Ive J 2022 年 3 月 22 日
I have an array [1 5 8 10] and using movmean with window length [0 1] this gives me [3 6.5 9 10]. Is there a way in which I can use movmean to calculate the mean of 10 and 1 as well and add that in the fourth position of the array?

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Ive J
Ive J 2022 年 3 月 22 日
What about this?
a = [1 5 8 10];
ma = movmean([a, a(1)], [0 1], 'Endpoints', 'discard')
ma = 1×4
3.0000 6.5000 9.0000 5.5000
  2 件のコメント
Ive J
Ive J 2022 年 3 月 22 日
Just set dim to 2:
a = [1 5 8 10;3 4 5 12];
ma = movmean([a, a(:, 1)], [0 1], 2, 'Endpoints', 'discard')
ma = 2×4
3.0000 6.5000 9.0000 5.5000 3.5000 4.5000 8.5000 7.5000

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