Fitting a modified gaussian

14 ビュー (過去 30 日間)
Sanchit Sharma
Sanchit Sharma 2022 年 3 月 18 日
コメント済み: Mathieu NOE 2022 年 3 月 21 日
Hello Experts,
I am new to data fitting. I would be very gratefull for a detailed response. I have a data set that looks like a streched gaussian distribution, or a reverse log normal distribution please see attached plot. Please let me know what distribution will be the best to get a good fit for this type of data. If you could please provide me with an example that would be very helpful. I have attached x and y data for your reference.
Thanks very much!
load x
load y
plot(x, y)

採用された回答

Mathieu NOE
Mathieu NOE 2022 年 3 月 21 日
hello
I am by no mean a curve fitting or stats expert but this is what I could achieve :
this is a reverse log normal distribution - so basically a gaussian fit realized not on x but on exp(x/constant)
f = @(a,b,c,d,x) a.*exp(-(exp(x/d)-b).^2 / c.^2);
plot
code
load('x.mat');
load('y.mat');
% curve fit using fminsearch
f = @(a,b,c,d,x) a.*exp(-(exp(x/d)-b).^2 / c.^2);
obj_fun = @(params) norm(f(params(1), params(2), params(3), params(4),x)-y);
d_init = 1000;
[a_init,ind] = max(y);
b_init = exp(x(ind)/d_init);
sol = fminsearch(obj_fun, [a_init,b_init,b_init/2,d_init]);
a_sol = sol(1)
b_sol = sol(2)
c_sol = sol(3)
d_sol = sol(4)
xx = linspace(min(x),max(x),200);
y_fit = f(a_sol, b_sol,c_sol,d_sol, xx);
yy = interp1(x,y, xx);
Rsquared = my_Rsquared_coeff(yy,y_fit); % correlation coefficient
plot(xx, y_fit, '-',x,y, 'r .', 'MarkerSize', 15)
title(['Gaussian Fit / R² = ' num2str(Rsquared) ], 'FontSize', 15)
ylabel('Amplitude', 'FontSize', 14)
xlabel('x', 'FontSize', 14)
eqn = " y = "+a_sol+ " * exp(-(exp(x / " +d_sol+" )- " +b_sol+")² / (" +c_sol+ ")²";
legend(eqn)
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
function Rsquared = my_Rsquared_coeff(data,data_fit)
% R2 correlation coefficient computation
% The total sum of squares
sum_of_squares = sum((data-mean(data)).^2);
% The sum of squares of residuals, also called the residual sum of squares:
sum_of_squares_of_residuals = sum((data-data_fit).^2);
% definition of the coefficient of correlation is
Rsquared = 1 - sum_of_squares_of_residuals/sum_of_squares;
end
  2 件のコメント
Sanchit Sharma
Sanchit Sharma 2022 年 3 月 21 日
Thanks very much! This was very helpful. Could you please elaborate the meaning of line:
obj_fun = @(params) norm(f(params(1), params(2), params(3), params(4),x)-y);
Also, why did you assume c_init = b_init/2?
Best,
S
Mathieu NOE
Mathieu NOE 2022 年 3 月 21 日
hello again
for the first question, I would simply recommend to see the fminsearch documentation. Simply follow how the function to minimize is defined (handle);
c_init = b_init/2 : a rough estimate based on how narrow or wide is the experimental peak. You can probably try other ratios , the optimizer will still converge to the optimal value
All the best !
M

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeProbability Distributions についてさらに検索

タグ

製品


リリース

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by