Error using a for-loop

The following gives an error and I don't know why. The code runs perfectly when I leave '(i_testen)' away behind 'Enkel_hoek_afg'.

   for i_testen=1:5
...
Enkel_hoek_afg(i_testen) = Enkel_hoek(1:Afg_c_RANK_RKNE(2,1))
end

Error: In an assignment A(I) = B, the number of elements in B and I must be the same.

Answer 1

[Star Strider]

See if this solves it:

for i_testen=1:5
...
Enkel_hoek_afg(i_testen,:) = Enkel_hoek(1:Afg_c_RANK_RKNE(2,1))
end

This assumes ‘Enkel_hoek(1:Afg_c_RANK_RKNE(2,1))’ is a row vector of constant length.

If it is not, create a cell array instead:

Enkel_hoek_afg{i_testen} = Enkel_hoek(1:Afg_c_RANK_RKNE(2,1))

Note that here, curly brackets ‘{}’ replace parentheses ‘()’ on the left-hand side of this assignment.

[Sam]

Matlab still gives an error :(

[Star Strider]

Does it throw an error for the cell array? It shouldn’t.

If it throws an error for the first option:

Enkel_hoek_afg(i_testen,:) = Enkel_hoek(1:Afg_c_RANK_RKNE(2,1))

what are the row and column sizes of ‘Enkel_hoek’?

What is the value stored in ‘Afg_c_RANK_RKNE(2,1)’ when it throws the error?

[Sam]

It gives the following error: Subscripted assignment dimension mismatch. Enkel_hoek is 677x1 Afg_c_RANK_RKNE is 2x1 and has values 0 for (1,1) and 328 for (2,1). But this value 328 changes for each measurement.

[Star Strider]

If the length changes with each iteration, use my cell array solution instead:

Enkel_hoek_afg{i_testen} = Enkel_hoek(1:Afg_c_RANK_RKNE(2,1))

Note that here, curly brackets ‘{}’ replace parentheses ‘()’ on the left-hand side of this assignment.

[Sam]

Strange, when I tried it the first time it didn't work. Now I've tried it again, and it works... Well, thanks a lot!

[Star Strider]

My pleasure!