How to plot all contour lines in one plot?

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Jorge Arturo Clares Pastrana
Jorge Arturo Clares Pastrana 2022 年 3 月 15 日
コメント済み: Star Strider 2022 年 3 月 15 日
Giiven a function f(x) I need to Plot the level sets contour lines where 𝑓(x) = −4.34, −4.3, −4.2, −4.1, −4, −3, −2, −1, 0.
Plot all of them in one graph

採用された回答

Star Strider
Star Strider 2022 年 3 月 15 日
Specify them as a single levels vector —
[X, Y, Z] = peaks(50);
figure
contour(X, Y, Z, [-4.34, -4.3, -4.2, -4.1, -4, -3, -2, -1, 0], 'ShowText',1)
colormap(turbo)
.
  2 件のコメント
Jorge Arturo Clares Pastrana
Jorge Arturo Clares Pastrana 2022 年 3 月 15 日
Thnakyou.
z = -4*x - 2*y - x^2 + 2*x^4 - 2*x*y + 3*y^2;
when i input the following equation for z it outputs a blank post do you know why?
Star Strider
Star Strider 2022 年 3 月 15 日
First, the function needs to be vectorised so that it can do element-wise calculations. Otherwise, it could be because for the values of ‘x’ and ‘y’ you are using, ‘z’ has no values in the range of the desired contours. Also, ‘x’ and ‘y’ must be matrices, not vectors, although I suspect that would throw a specific error.
Use your values for ‘x’ and ‘y’ in something like this example code —
z = @(x,y) -4*x - 2*y - x.^2 + 2*x.^4 - 2*x.*y + 3*y.^2; % Vectorised Anonymous Function For 'z'
x = linspace(-5, 5, 150);
y = linspace(-5, 5, 150);
[X,Y] = ndgrid(x, y);
Z = z(X,Y);
figure
contour(X, Y, Z, [-4.34, -4.3, -4.2, -4.1, -4, -3, -2, -1, 0], 'ShowText',1)
colormap(turbo)
axis([-1 2 -1 2])
.

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その他の回答 (1 件)

Jorge Arturo Clares Pastrana
Jorge Arturo Clares Pastrana 2022 年 3 月 15 日
Thnakyou.
z = -4*x - 2*y - x^2 + 2*x^4 - 2*x*y + 3*y^2;
when i input the following equation for z it outputs a blank post do you know why?

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